C. 20Ne
19F has 19-9=10 neutrons
Ne=20-10=10 neutrons
Explanation:
Hydrogen atoms of one water molecule are attracted towards the oxygen atom of a neighboring water molecule can be termed as an intramolecular bond.
Generally, the oxygen atom is partially negatively charged, and the hydrogen atom is partially positively charged, so an arttraction occurs which forms this hydrogen bond. The attraction of the O-H bonding electrons towards the oxygen atom leaves a deficiency on the far side of the hydrogen atom relative to the oxygen atom. The result is that the attractive force between the O-H hydrogen and the O-atom of a nearby water molecule is strong.
This hypothetical process would produce actinium-230.
An alpha decay reduces the atomic number of a nucleus by two and its mass number by four.
There are two types of beta decay: beta minus β⁻ and beta plus β⁺.
The mass number of a nucleus stays the same in either process. In β⁻ decay, the atomic number increases by one. An electron e⁻ is produced. In β⁺ decay, the atomic number decreases by one. A positron e⁺ is produced. Positrons are antiparticles of electrons.
β⁻ are more common than β⁺ in decays involving uranium. Assuming that the "beta decay" here refers to β⁻ decay.
Gamma decays do not influence the atomic or mass number of a nucleus.
Uranium has an atomic number of 92. 238 is the mass number of this particular isotope. The hypothetical product would have an atomic number of 92 - 2 ⨯ 2 + 1 = 89. Actinium has atomic number 89. As a result, the product is an isotope of actinium. The mass number of this hypothetical isotope would be 238 - 2 ⨯ 4 = 230. Therefore, actinium-230 is produced.
The overall nuclear reaction would involve five different particles. On the reactant side, there is
On the product side, there are
Consider: what would be the products if the nucleus undergoes a β⁺ decay instead?
D. CIF3
got it correct on test <3
(2) Add 30. g of solute to 970. mL of solvent to make 1.0 L of solution.
(3) Add 1000. g of solvent to 30. g of solute.
(4) Add enough solvent to 30. g of solute to make 1.0 L of solution.
A student wants to prepare a 1.0-liter solution of a specific Molarity. The student determines that the mass of the solute needs to be 30. grams. Add enough solvent to 30. g of solute to make 1.0 L of solution.
The proportion of solute moles to solution length is known as molarity. By dividing the number of moles of HCl by the volume (L) of the solution in which it was dissolved, we may get the acid solution's molarity.
A chemical species' concentration in a solution, specifically the amount of a solute per unit volume of solution, is measured by its molar concentration.
A mole is a unit of measurement for a chemical substance, and it is from this unit that the word "molarity" is derived. The method of figuring out how much of a material a certain chemical solution contains is known as molecularity, sometimes known as the molar concentration of a solution.
Thus, option 4 is correct.
To learn more about molarity, follow the link;
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