b. compound
c. solution
d. suspension
e. colloid
The substances that can't be separated into simpler substances or converted into other substances by chemical processes are elements. They are fundamental substances and cannot be changed into other elements through chemical processes. The correct answer to the given question is option a. elements
The answer to your question is a. elements. In chemistry, elements are substances that cannot be separated into simpler substances or converted into another substance by chemical processes.
This is what makes them fundamental substances. Chemical processes can change compounds, solutions, suspensions, and colloids into different substances, but they cannot change an element into a different element. For example, hydrogen is an element that cannot be converted into any other element through chemical processes. It is fundamentally hydrogen.
The correct answer to the given question is option a. elements
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The is Answer is air
Answer:
The rubber becomes brittle and can break in your hand. The explanation for why this happens concerns cross-linking bonds. Ultra-violet light from the sun provides the polymer molecules with the activation energy they need to be able to form more cross-links with other chains.
If excessively excessive cross-links are formed in rubber, it becomes overly rigid and brittle, hampering its natural elasticity and strength. The increase in cross-links restricts the moving of the polymer chains, undermining the effectiveness of the rubber in many applications.
The formation of cross-links in rubber significantly affects its properties. In the case where too many cross-links are formed, the rubber is likely to become overly rigid and brittle. This is because the cross-links restrict the movement of the polymer chains, which reduces flexibility and elasticity. As a result, too many cross-links can compromise the usefulness of rubber for many applications, which require its natural elasticity and strength. For example, in a rubber band, if too many cross-links were formed, then it would be less stretchy and snap more easily when stretched.
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Kp = 5.7, 1200K
Calcualte the total pressure at equilibrium when 4.45g CO2 is introduced into a 10.0L container and heated to 1200K in the presence of 2.00g of graphite