Answer:
The tension in the part of the cord attached to the textbook is 6.58 N.
Explanation:
Given that,
Mass of textbook = 2.09 kg
Diameter = 0.190 m
Mass of hanging book = 3.08 kg
Distance = 1.26 m
Time interval = 0.800 s
Suppose,we need to calculate the tension in the part of the cord attached to the textbook
We need to calculate the acceleration
Using equation of motion
Put the value into the formula
We need to calculate the tension
When the book is moving with acceleration
Using formula of tension
Hence, The tension in the part of the cord attached to the textbook is 6.58 N.
A. 5,362.56 N
B. 7,600.18 N
C. 6,700.56 N
D. 6,150.64 N
Answer:The answer for PF students is D.
Explanation:
Potential Energy of the ball.
0784 Joules
7,683 Joules
80 Joules
O 0.8 Joules
Answer:
Answer - 75cm=0.075 decametre (divide the length value by 1000.)
75cm=0.00075 kilometer (divide the length value by 100000).