In which state of matter are particles packed tightly together and stay in fixed positions?

Answers

Answer 1
Answer: solid..................

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An advertisement claims that a certain 1200kg can accelerate from rest to a speed of 25 m/s in a time of 8s. What average power must the motor develop to produce this acceleration if the car is going up a 20 degree incline? Give your answer in Watts. Ignore friction.

A textbook of mass 2.09 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose diameter is 0.190 m, to a hanging book with mass 3.08 kg. The system is released from rest, and the books are observed to move a distance 1.26 m over a time interval of 0.800 s.

Answers

Answer:

The tension in the part of the cord attached to the textbook is 6.58 N.

Explanation:

Given that,

Mass of textbook = 2.09 kg

Diameter = 0.190 m

Mass of hanging book = 3.08 kg

Distance = 1.26 m

Time interval = 0.800 s

Suppose,we need to calculate the tension in the part of the cord attached to the textbook

We need to calculate the acceleration

Using equation of motion

y=ut+(1)/(2)at^2

a=(2y)/(t^2)

Put the value into the formula

a=(2*1.26)/(0.800)

a=3.15\ m/s^2

We need to calculate the tension

When the book is moving with acceleration

Using formula of tension

T=ma

T=2.09*3.15

T=6.58\ N

Hence, The tension in the part of the cord attached to the textbook is 6.58 N.

A steel block has a volume of 0.08 m³ and a density of 7,840 kg/m³. What is the force of gravity actingon the block (the weight) in water?
A. 5,362.56 N
B. 7,600.18 N
C. 6,700.56 N
D. 6,150.64 N

Answers

The mass of the block is

         (0.08 m³) x (7,840 kg/m³)  =  627.2 kg.

The force of gravity on the block is

                         (mass) x (gravity)

                     =  (627.2 kg) x (9.8 m/s²)

                     =    6,146.6 newtons .

As long as the block is on Earth, that's its weight.  In vacuum, in air,
in water, in sugar, in bed, in trouble, or in molasses ... that's the force
of gravity attracting it toward the center of the Earth.

If it happens to be in water, then there's another force acting on it ...
the upward force of buoyancy, equal to the weight of the water it
displaced.

The block displaced 0.08 m³ of water, so the buoyant force is the weight
of 0.08 m³ of water.

The density of water is 1,000 kg/m³, so the mass of the displaced
water is

                      (0.08 m³) x (1,000 kg/m³)  =  80 kg .

and its weight is  (80 kg) x (9.8 m/s²)  =  784 newtons.

That's the buoyant force on the block . . . 784 newtons.
It acts upward on the block, opposite to the force of gravity.
So, if there's a bathroom scale on the bottom of the pool,
and the block is resting on it, the scale will read

                 (actual weight) minus (buoyant force)

             = (6,146.6 newtons) - (784 newtons)  =  5,362.6 newtons .   

The real weight of the block is 6146.6 newtons.
That's choice-D.

The apparent weight of the block in water is 5,362.6 newtons.
That's choice-A.

The question asked for the force of gravity on the block, and then
in parentheses it says (weight).  Both of these are 6146.6 newtons.

If you answer 'D', and your answer is marked wrong and somebody
tries to tell you that the correct answer is 'A', then I want you to either
show them what I have written here, or else tell them to come see me,
and I will straighten them out.

Answer:The answer for PF students is D.

Explanation:

Which of the following is a physical property of wood

Answers

Hard, Brown, Smells of timber or forest

The density, hard, strong, and rough.

State the law of universal gravitation, and use examples to explain how changes in mass and changes in distance affect gravitational force.

Answers

F(g)= Gm1m2/ r^2 If mass is increased, so will the force of gravity because it is in direct relationship with the gravitational force, but if distance is increased, the force of gravity will decrease because it is indirectly related ( since it is on the bottom of the equation)

Question 1 (Mandatory) (1 point)An 8 kg basketball is dropped from a height of 10 m. Calculate the Gravitational
Potential Energy of the ball.
0784 Joules
7,683 Joules
80 Joules
O 0.8 Joules

Answers

Answer:

P.E=mgh \n  = 8kg * 9.81m {s}^( - 2)  * 10m = 784J

75 Centimeters to decameters and Kilometer​

Answers

Answer - 75cm=0.075 decametre (divide the length value by 1000.)

75cm=0.00075 kilometer (divide the length value by 100000).