Answer:
There you go
Explanation:
When a physical change occurs, the mass of the substance is conserved. This means that the total mass of the substance remains the same from beginning to end. The physical properties of the substance, such as size and shape, may change, but the amount of matter in the substance does not change.
Answer:
The motion graph provided represents the displacement of a toy train over time. The graph consists of two distinct segments: an initial period of constant velocity followed by a period of rest.
From the given information, we can determine that the train starts from a position of 2.0m north. This means that at t=0 (the beginning of the graph), the train is located 2.0m north of its starting point.
The first segment of the graph shows a straight line with a positive slope, indicating constant velocity. Since the train is moving north, the positive slope suggests that it is moving in the positive direction along the y-axis. The steeper the slope, the greater the velocity.
The second segment of the graph shows a horizontal line, indicating that the train is at rest. During this period, the train does not undergo any displacement and remains stationary.
To determine the total displacement of the train, we need to calculate the area under the graph. In this case, we have two separate areas to consider: one for each segment.
For the first segment, which represents motion, we can calculate the area by finding the area of a triangle. The formula for calculating the area of a triangle is A = 1/2 * base * height. In this case, the base corresponds to the time interval and the height corresponds to the displacement.
Let's assume that each unit on both axes represents 1 second and 1 meter, respectively. From the graph, we can estimate that the time interval for the first segment is approximately 4 seconds and that the displacement is approximately 8 meters (from t=0 to t=4). Therefore, using our formula, we can calculate:
A = 1/2 * 4s * 8m = 16m²
So, during this period of motion, the train has a displacement of 16 meters.
For the second segment, which represents rest, the train does not undergo any displacement. Therefore, the area under the graph is zero.
To calculate the total displacement of the train, we sum up the areas from both segments:
Total displacement = 16m² + 0m² = 16m²
Hence, the total displacement of the toy train is 16 meters.
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B
C
D
Answer:
A
Explanation:
The figure shows the electric field produced by a spherical charge distribution - this is a radial field, whose strength decreases as the inverse of the square of the distance from the centre of the charge:
More precisely, the strength of the field at a distance r from the centre of the sphere is
where k is the Coulomb's constant and Q is the charge on the sphere.
From the equation, we see that the field strength decreases as we move away from the sphere: therefore, the strength is maximum for the point closest to the sphere, which is point A.
This can also be seen from the density of field lines: in fact, the closer the field lines, the stronger the field. Point A is the point where the lines have highest density, therefore it is also the point where the field is strongest.
Answer:
3.75m/s²
Explanation:
g= GM/r²
For planet 1
= GM/r² (i)
= 15m/s²
for planet 2
radius= 2*r= 2r
g= GM/r
= GM/(2r)²
= GM/4r²
= GM/r² *1/4
from (i)
= *1/4
= 15/4
= 3.75m/s²
The statements which describe the principles of the big bang theory include:
Big bang theory was postulated by Georges Lemaître and he is regarded as
the father of this principle. This principle talks about how the universe was
formed.
He proposed that the universe was formed from a single point which then
began expanding and stretching to accommodate more components.
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Answer:
A and B
Explanation:
edge 2023
a. True
b. False
Answer: True.
Kepler was an astronomer, astrologer and mathematician. He was an apprentice of Tycho Brahe, other big (maybe the biggest) astronomer of their time.
Kepler is best known for his 3 laws of planetary motion.
1) the orbit of a planet is an ellipse with the Sun at one of the two foci
2) A line segment joining a planet and the Sun sweeps out equal areas during equal intervals of time
3) The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.