PHYSICS HIGH SCHOOL

A car has a speed of 2 m/s and a mass of 1500kg. What is the car’s kinetic energy

Answers

Answer 1
Answer:

Answer:

3,000 m/s

Explanation:

3,000 m/s

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A car weighs 186 N. It's being pushed forward by its engine with a force of 942 N.1. What is the normal force acting on the car by the road?
N
2. What is the force of friction acting on the car by the road?.
N
3. What is the coefficient of kinetic friction between the car and the road?

Answers

Ok that a good question

Please help hurry. It’s time.

Answers

Answer: a

Explanation: Hope it helps

Answer:

A

Explanation:

I think its a because A would be heavier making it go down faster than B. its like when you drop a father compared to a ball, the feather is lighter so it will go down slower than the ball because it has more mass

What happens as a result of an increase in the intensity of a sound wave? -the frequency of a soundwave increases. -the velocity of the sound wave decreases. -the energy of the soundwave increases. -the amplitude of the soundwave decreases

Answers

As a result of an increase in the intensity of a sound wave, the energy of the sound wave increases!

Answer: c. The energy of the sound wave increases.

Explanation:

The study of celestial objects in the universe describes which field of physical science?a. Physics
b. Chemistry
c. Astronomy
d. None of the above User: Scientific knowledge is

Answers

C. astronomy because astronomy is the study of the universe, the stars, etc.

What is the smallest value of the force F such that the 8.0 kg block will not slide down the wall? The coefficient of static friction between the block and the wall is 0.4.Select one:

a. 10N

b. 100N

c. 200N

d. 98N

Answers

The smallest value of the force that will make the block not to slide down is 10 N.

We'll begin by calculating the normal reaction. This can be obtained as follow:

  • Mass (m) = 8 Kg
  • Acceleration due to gravity (g) = 10 m/s²
  • Normal reaction (N) =?

N = mg

N = 8 × 10

N = 80 N

Finally, we shall determine the frictional force.

  • Coefficient of friction (μ) = 0.4
  • Normal reaction (N) = 80 N
  • Frictional Force (F) =?

F = μN

F = 0.4 × 80

F = 32 N

Since the frictional force is 32 N, therefore, a force lesser than the frictional force will make the blocknot to slide down.

From the options given above, only option A has a force that is lesserthan the frictional force.

Therefore, the correct answer to the question is Option A. 10 N

Learn more about frictional force:

brainly.com/question/20049999

Final answer:

The smallest value of the force that will not slide the 8.0 kg block down the wall is 31.36 N.

Explanation:

To determine the smallest value of the force such that the 8.0 kg block will not slide down the wall, we need to consider the static friction between the block and the wall. The formula for static friction is fs = μs * N, where μs is the coefficient of static friction and N is the normal force. In this case, the normal force is equal to the weight of the block, which is mg = 8.0 kg * 9.8 m/s^2 = 78.4 N. Therefore, the smallest value of the force is equal to the maximum static friction force, which can be calculated as fs = 0.4 * 78.4 N = 31.36 N. So the correct answer is 31.36 N.

Learn more about Static Friction here:

brainly.com/question/13000653

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Imagine that you are working as a roller coaster designer. You want to build a record breaking coaster that goes 70.0 m/s at the bottom of the first hill. You estimate that the efficiency of the tracks and cars you are using 90.0%. How high must the first hill be?

Answers


Wow !  This is not simple.  At first, it looks like there's not enough information, because we don't know the mass of the cars.  But I"m pretty sure it turns out that we don't need to know it.

At the top of the first hill, the car's potential energy is

                                  PE = (mass) x (gravity) x (height) .

At the bottom, the car's kinetic energy is

                                 KE = (1/2) (mass) (speed²) .

You said that the car's speed is 70 m/s at the bottom of the hill,
and you also said that 10% of the energy will be lost on the way
down.  So now, here comes the big jump.  Put a comment under
my answer if you don't see where I got this equation:

                                   KE = 0.9  PE

        (1/2) (mass) (70 m/s)² = (0.9) (mass) (gravity) (height)     

Divide each side by (mass): 

               (0.5) (4900 m²/s²) = (0.9) (9.8 m/s²) (height)

(There goes the mass.  As long as the whole thing is 90% efficient,
the solution will be the same for any number of cars, loaded with
any number of passengers.)

Divide each side by (0.9):

               (0.5/0.9) (4900 m²/s²) = (9.8 m/s²) (height)

Divide each side by (9.8 m/s²):

               Height = (5/9)(4900 m²/s²) / (9.8 m/s²)

                          =  (5 x 4900 m²/s²) / (9 x 9.8 m/s²)

                          =  (24,500 / 88.2)  (m²/s²) / (m/s²)

                          =        277-7/9    meters
                                  (about 911 feet)
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