During exercise, the amount of ____________ carried in the blood to the muscles increases.

Answers

Answer 1
Answer: The correct answer is: Oxygen

Explanation:
In order to function properly (movement etc.) during exercise, muscles require oxygen. During exercise, the depth as well as the rate of breathing increase, which in turn increases the amount of oxygen inhaled. In order to expand and contract lungs and for other bodily movements, muscles require oxygen, and for that, more oxygen is carried in the blood to muscles. Hence, the correct answer is Oxygen.
Answer 2
Answer:

Your answer would be oxygen because when doing moderate to vigorous workouts, your body needs more oxygen to be supplied to your muscles.


Related Questions

An unknown fiber sample is found at a crime scene. Forensic scientists measure its index of refraction and obtain a value of 1.48. A suspect's jacket was made of Dacron polyester, his jeans were made of cotton, his shirt was made of rayon, and his tie was made of acetate. Which piece of clothing may match the fiber at the crime scene?Question 12 options:tieshirtjeansjacket
What are the 3 types of mediums that sound can travel through
Wich is a scalar quantity (1)velocity (2)speed (3)acceleration (4) displacement
Predict whether the changes in enthalpy, entropy, and free energy will be positive or negative for the melting of ice, and explain your predictions. How does temperature affect the spontaneity of this process?
Which of the following does not represent a mechanical wave?sound waves in the ocean waves in a wheat field light

The general consensus is that our policymakers do not know what they are doing and are managing our economy ineffectively

Answers

Answer:

True.

This is because, from the information provided so far, it could be concluded that, the policy makers don't have any single idea of what they are doing regarding to the economy.

This could be seen in the series of poor performance of the economic indicators as shown which has lead to poor economic growth in our country.

Explanation:

10. Which of the following statements is accurate?A. Sound waves passing through the air will do so as transverse waves, which vibrate vertically and still retain their horizontal
positions.
B. Compressions and rarefactions occur throughout a transverse wave.
C. The wavelength of both traverse and longitudinal waves is measured parallel to the direction of the travel of the wave.
D. Amplitude of longitudinal waves is measured at right angles to the direction of the travel of the wave and represents the
maximum distance the molecule has moved from its normal position.

Answers

Before coming into conclusion first we have to understand the nature of longitudinal wave and transverse wave.

The longitudinal wave is a type of mechanical wave in which the direction of wave propagation is parallel to the particle vibration.In such type of wave one will notice compressions and rarefactions.

Compressions are the high pressure zones where the particles are very close to each other and rarefactions are the low pressure regions where there is  large separation between particles. Hence a longitudinal wave is a series of compresions and rarefactions.

The wavelength of a longitudinal  wave is the distance between two successive compressions or rarefactions. Hence the wavelength is measured parallel to the direction of wave.  As the particle vibration is parallel to wave propagation ,so the amplitude of the wave is measured parallel to wave direction.

Transverse wave is such type of mechanical wave in which the particle vibration is perpendicular to wave propagation.Here crests and troughs are formed.

The distance between two successive crests or troughs are called wavelength which is measured parallel to the wave propagation. As the particle vibration is perpendicular to wave propagation,so the amplitude of the wave is measured perpendicular to the wave propagation.It is so because  amplitude of the wave is the maximum distance travelled by the particle from equilibrium position.

Out of the four options given in the question only the option 3 is correct .Other options are wrong as violate the nature of longitudinal and transverse waves.

Answer:

C. The wavelength of both traverse and longitudinal waves is measured parallel to the direction of the travel of the wave.

Explanation:

The speed of sound is 330 m/s and the wavelength of a particular sound wave is 33 meters. Calculate the period of this wave.

Answers

Answer:

The period of this wave es 10 seconds.

Explanation:

The wavelength is the minimum distance between two points of the wave that is in the same state of vibration.

Frequency is the number of vibrations that occur in a unit of time.

The speed of propagation is the speed with which the wave propagates in the middle. Relate wavelength (λ) and frequency (f) inversely proportionally using the following equation: v = f * λ.

The period is the time that elapses between the emission of two consecutive waves. In other words, it is the time it takes for a complete wave to pass through a reference point. The period (T) is simply the inverse of the frequency (f):

T=(1)/(f)

The units of the period are the seconds (s)

Then the propagation speed will be v = λ / T (Speed = wavelength/period)

Then T=  λ / v

Period =  (speed)/(wavelength) = (330 (m)/(s) )/(33 m)

Period (T)= 10 s

The period of this wave es 10 seconds.

Answer:

.10 sec

Explanation:

Snowshoes enable a person to walk on deep snow because the snowshoesa. decrease the person’s weight on the snow.
b. increase the area over which the person’s weight is distributed.
c. increase the pressure on the snow.
d. increase the buoyancy of the person.

Answers

Answer:

Option B is correct.

Explanation:

Snowshoes has large area of crossection.

As a person wears the snowshoes, the weight of the person distributed over a large area and thus the pressure exerted by the surface due to the weight of the person is less.

The relation among pressure, force and area of crossection is given below.

Pressure = (Force)/(Area of crossection)

As area of crossection is large, pressure is small and thus the person walk on deep snow.

At its closest point, Mercury is approximately 46 million kilometers from the sun. What is this distance in AU?

Answers

This problem can be solved using the following relation: 1 kilometer = 6.6846e-9 AU. Since we are already given the number of kilometers, we simply have to multiply it to its equivalent in AU to solve for the equivalent distance. This is done below:

46 000 000 * 6.6846e-9 = 0.3 AU

Comic strip hero Superman meets an asteroid in outer space and hurls it at 100 m/s. The asteroid is on thousand times more massive than superman is. In the strip, superman is seen at rest after the throw. Taking physics into account, what would be his recoil speed?

Answers

Answer:

Recoil speed = -100,000 m/s

Explanation:

First, this is an exercise that has relation with angular momentum.

So, you need to use the expressions for momentum.

Now, we can assume that Superman and the asteroid are initially at rest, so both moments are 0.

If superman hurls the asteroid, this means that  he should have an equal moment but in the opposite direction of the asteroid, therefore, he also have an opposite recoil moment.

The expression to use is the following:

innitial momentum = final momentum

The final momentum, is the combination of superman recoil moment, and the asteroid so:

0 = Mass * Velocity

Let M1 and V1 be the mass and velocity of superman, while M2 and V2 would be the asteroid, thus we have:

0 = M1 * V1 + M2 * V2

As the problem states, the asteroid is 1000 times more massive than superman, so we can say that M2 = 1000M1. Replacing in the above expression we finally have:

0 = M1 * V1 + 1000M1 * V2

M1 * V1 = -1000M1V2 -----> Simplify M1

V1 = -1000V2

V1 = -1000 * 100

V1 = -100,000 m/s

This would be the recoil speed of Superman.

Answer:

-100,000m/s

Explanation: