Solve the system of equations below by graphing them with a pencil andpaper. Enter your answer as an ordered pair.
y=-x+ 2
y=-2x+6

Answers

Answer 1
Answer:

Answer:

x=2 y=0

Step-by-step explanation:

Explanation:

just put y= -x in second equation x comes out to be 2. Then put x=2 y comes out to be 0


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In a poll conducted by the Gallup organization in April 2013, 48% of a random sample of 1022 adults in the U.S. responded that they felt that economic growth is more important than protecting the environment. We can use this information to calculate a 95% confidence interval for the proportion of all U.S. adults in April 2013 who felt that economic growth is more important than protecting the environment. Make sure to include all steps.
I travelled at 60km/hour and took 2hours for a certain journey.How long would it have taken me if I had travelled at 50km/hour?​
How many cups are in 3 gallons? 1 gallon = 16 cupsLabel your answer in cups.
(c) Is it possible for an n × n matrix A to satisfy A3 = In without A being invertible? Explain

1 For a recipe, Paul uses 3 cups of sugar for every 4 cups of flour. Which table showsequivalent ratios for this recipe?

Answers

The equivalent ratios of the cups of sugar to cups of flour are shown in table B.

What are ratios and proportions?

An ordered pair of numbers a and b, represented as a / b, is a ratio if b is not equal to 0. A proportion is an equation that sets two ratios at the same value. The numerical relationship between two values demonstrates how frequently one value contains or is contained within another.

Given that for a recipe, Paul uses 3 cups of sugar for every 4 cups of flour. Check the table number B for the ratios of the cups of sugar to cups of flour,

Cups of sugar   Cups of flour      ratio

3                              4                     3 / 4 = 0.75

6                              8                     6 / 8 = 0.75

9                             12                   9 / 12 = 0.75

12                            16                   12 / 16 = 0.75

Hence, the table which shows the equivalent ratio is B

To know more about ratios and proportions follow

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Answer:

B

Step-by-step explanation:

In the chart for b it shows the use of 3 cups of sugar per 4 cups of flour which is what the question wants you to find.

The shape of the distribution of the time required to get an oil change at a 15-minute oil-change facility is unknown. However, records indicate that the mean time is 16.2 minutes, and the standard deviation is 3.4 minutes.Requried:
a. What is the probabilty that a random sample of n = 40 oil changes results in a sample mean time less than 15 minutes?
b. Suppose the manager agrees to pay each employee a​ $50 bonus if they meet a certain goal. On a typical​ Saturday, the​ oil-change facility will perform 40 oil changes between 10 A.M. and 12 P.M. Treating this as a random​ sample, there
would be a​ 10% chance of the mean​ oil-change time being at or below what​ value? This will be the goal established by the manager.

Answers

Answer:

(a) Probability that a random sample of n = 45 oil changes results in a sample mean time < 10 ​minutes i=0.0001.

(b) The mean oil-change time is 15.55 minutes.

Step-by-step explanation:

Let us denote the sample mean time as x

From the Then x = mean time = 16.2 minutes

  The given standard deviation = 3.4 minutes

The value of  n sample size = 45

CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

If two objects travel through space along two different curves, it's often important to know whether they will collide. (Will a missile hit its moving target? Will two aircraft collide?) The curves might intersect, but we need to know whether the objects are in the same position at the same time. Suppose the trajectories of two particles are given by the vector functions for t 0. Do the particles collide? If they collide find t. If not enter NONE.r1(t)=r2(t)=<9t-14,t^2,13t-42>t=

Answers

Answer:

The particles collide when t = 7 at the point (49, 49, 49).

Step-by-step explanation:

We know the trajectories of the two particles,

r_1(t)=\langle t^2,16t-63,t^2\rangle\nr_2(t)=\langle 9t-14,t^2,13t-42\rangle

To find if the tow particles collide you must:

  • Equate the x-components for each particle and solve for t

t^2=9t-14\nt^2-9t+14=0\n\left(t^2-2t\right)+\left(-7t+14\right)=0\nt\left(t-2\right)-7\left(t-2\right)=0\n\left(t-2\right)\left(t-7\right)=0

The solutions to the quadratic equation are:

t=2,\:t=7

  • Equate the y-components for each particle and solve for t

16t-63=t^2\n^2-16t+63=0\n\left(t^2-7t\right)+\left(-9t+63\right)=0\nt\left(t-7\right)-9\left(t-7\right)=0\n\left(t-7\right)\left(t-9\right)=0

The solutions to the quadratic equation are:

t=7,\:t=9

  • Equate the z-components for each particle and solve for t

t^2=13t-42\nt^2-13t+42=0\n\left(t^2-6t\right)+\left(-7t+42\right)=0\nt\left(t-6\right)-7\left(t-6\right)=0\n\left(t-6\right)\left(t-7\right)=0

The solutions to the quadratic equation are:

t=6,\:t=7

Evaluate the position vectors at the common time. The common solution is when t = 7.

r_1(7)=\langle 7^2,16(7)-63,7^2\rangle=\langle 49,49,49\rangle\n\nr_2(7)=\langle 9(7)-14,7^2,13(7)-42\rangle=\langle 49,49,49\rangle

For two particles to collide, they must be at exactly the same coordinates at exactly the same time.

The particles collide when t = 7 at the point (49, 49, 49).

WILL GIVE BRAINLYIST.For this problem, use the tables and charts shown in this section. For total cost of an American tourist traveling on the European continent, Is the average price (1) higher, or (2) lower than the highest total figure shown for the Pacific area? higher lowes​

Answers

Step-by-step explanation:

higher

Un recipiente cilíndrico tiene un diámetro de 160cm. y la misma altura. ¿Cuánto litros de agua puede caber?

Answers

Respuesta:

3215360 cm³

Explicación paso a paso:

Dado que :

Radio = 160/2 = 80 cm

Altura, h = 160 cm

Volumen de un cilindro = πr²h

Volumen del cilindro = π * 80² * 160

Volumen = 3215360 cm³

One question in the survey asked how much time per year the children spent in volunteer activities. The sample mean was 14.76 hours and the sample standard deviation was 16.54 hours.Required:

a. Based on the reported sample mean and sample standard deviation, explain why it is not reasonable to think that the distribution of volunteer times for the population of South Korean middle school students is approximately normal.
b. The sample size was not given in the paper, but the sample size was described as large. Suppose that the sample size was 500. Explain why it is reasonable to use a one-sample t confidence interval to estimate the population mean even though the population distribution is not approximately normal.
c. Calculate and interpret a confidence interval for the mean number of hours spent in volunteer activities per year for South Korean middle school children.

Answers

Answer:

a. If the distribution was normal, many values would be negative, what is incompatible with the response variable (hours dedicated to volunteer activities).

b. If the sample is big, accordingly to the Central Limit Theorem, the sampling distribution shape tends to be normally-like, so we can apply a one-sample t-test.

c. The 95% confidence interval for the mean is (13.307, 16.213).

Step-by-step explanation:

a. If the distribution was normal, the values with one or more standard deviation below the mean would be negative, what is incoherent for this case. This, in a normal distribution, represents approximately 16% of the values.

If we calculate the probabilty for a normal distribution with the sample parameters, the probability of having "negative hours" is 18.6% (see picture attached).

b. If the sample is big, accordingly to the Central Limit Theorem, the sampling distribution shape tends to be normally-like, so we can apply a one-sample t-test.

The sampling distribution standard deviation is also reduced by a factor of 1/√n.

c. We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=14.76.

The sample size is N=500.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=(s)/(√(N))=(16.54)/(√(500))=(16.54)/(22.3607)=0.7397

The t-value for a 95% confidence interval is t=1.965.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=1.965 \cdot 0.7397=1.453

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 14.76-1.453=13.307\n\nUL=M+t \cdot s_M = 14.76+1.453=16.213

The 95% confidence interval for the mean is (13.307, 16.213).