Answer:
The apparent weight is the weight of the body minus the weight of the liquid displaced. The body will float only when both the weights are same. In this case, the given body of weight W is floating and hence the apparent weight is zero.
Answer:
Zero
Explanation:
The apparent weight is the weight of the body minus the weight of the liquid displaced. The body will float only when both the weights are same. In this case, the given body of weight W is floating and hence the apparent weight is zero.
Explain your answer.
-Ethel is correct because energy is not carried from one place to another.
-Brody is correct because the pattern repeats.
-Ethel is correct because the motion has no pattern.
Also...
Khalad is measuring the amplitude of a wave. What can be known about this wave?
-It is a sound wave.
-It is a transverse wave.
-It is an electromagnetic wave.
-It is a mechanical wave.
The correct answer is:
B. Ethel is correct because energy is not carried from one place to another.
Brody and Ethel are arguing about waves. Brody says that waving his hand back and forth is a scientific wave. Ethel says that it is not. Ethel is correct because energy is not carried from one place to another.
The correct answer to the question is - A) Object's kinetic energy is transformed into mainly heat energy.
EXPLANATION:
The friction is the opposing force which acts tangentially between two surfaces when there is a relative velocity between them.
As per the question, the moving object comes to rest after the application of frictional force.
Initially the object is in motion.Hence, the energy possessed by the moving object is kinetic energy.
When frictional force is applied on the moving object, the kinetic energy of the moving object will be converted into mainly heat energy. It is due to the fact that friction causes heat production between two surfaces in contact.
Hence, correct option will be that the object's kinetic energy is transformed into mainly heat energy.
Answer:
θ = 19.47°
Explanation:
given,
mass of the barge = 1000 kg
force applied to pull = 80 N
direction = 30° west to north
force exerted by the cable = 120 N
direction = ?
first cable is pulling
in north direction = 80 cos ∅
= 80 cos 30°
= 69.28 N
in west direction = 80 sin ∅
= 80 sin 30°
= 40 N
the other cable will pull in the opposite direction of west
now,
θ = 19.47°
the direction of the cable will be equal to θ = 19.47°