Quiz 2 : percent and percentage change the decimal 0.82 to a percent


A. 0.8%
B.82%
C.90%
D. None of these choices are correct​

Answers

Answer 1
Answer:

Answer:

82%

Step-by-step explanation:

0.82x100=82

=82%

Hope this helps

Answer 2
Answer:

Answer:

B. 82%

Step-by-step explanation:

.82 can also be written as 82/100 and 82/100 can be turned into 82% because they are all based on 100


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9.87 x 10^7 - 2.5 x 10^6answer in scientific notation

Z = 19i + 14 what is the imaginary part

Answers

Answer:

The imaginary part is:  z = 19

Step-by-step explanation:

For real numbers a and b, a number written in form a+bi is called a acomplex number. The value a is called the real part and b is called the imaginary part of complex number.

In need of help asap! ? With steps

Answers

Answer:

<BAE is congruent to <DAC (first choice)

Step-by-step explanation:

Triangle ACD has three angles: <DAC, <ACD, <ADC

Triangle ABE has three angles: <BAE, <AEB, <ABE

Angles ACD, ADC, AEB and ABE are all different angles. Look them up in the figure, and you'll see they are 4 different angles.

Angles BAE and DAC are the same angle.

Answer: <BAE is congruent to <DAC (first choice)

If george earns q salary of $18,500 qnd 28% of it is deducted in taxes, how much take hime pay remains

Answers

Answer:

take home pay = $13,320

Step-by-step explanation:

28% of salary is taxed so take home pay = 72% of salary

= 72% * salary

= 0.72 * $18,500

= $13,320

Answer:

$13,320

Step-by-step explanation:

salary of $18,500

28% of it is deducted in taxes

take home pay = salary x (1 - tax)

= 18500 x (1 - 28%)

= 18500 x 0.72

= 13320

How do I solve the equation x/5 + 13 = 25

Answers

Answer:

(60)/(5)  + 13 = 25 \n 12 + 13 = 25

Step-by-step explanation:

25 =  (x)/(5)  + 13 \n 25 - 13 =  (x)/(5) \n 12 =  (x)/(5 )  \n 12 * 5 = x \n 60 = x

Answer:

x=60

Step-by-step explanation:

Move all terms not containing  x  to the right side of the equation.

Subtract  13from both sides of the equation.

x/5=25-13

Subtract  13  from  25.

x/5=12

Multiply both sides of the equation by  5.

5*x/5=5*12

Simplify both sides of the equation.

Cancel the common factor of  5.

x=5*12

Multiply  5  by  12.

x=60

Hope this helped!!

Have a great day!!

6 apple trees fir every 4 pears trees How many apple trees would there be if there were 42 pear trees

Answers

Answer: 63 apple trees
Explanation: divide 42 by 4 to get that amount of groups (10.5) then multiply that number by 6 so (10.5 • 6) and that should give the apple tree total.

. A coin is tossed three times, and the sequence of heads and tails is recorded.(a) Determine the sample space, Ω.(b) List the elements that make up the following events: i.A= exactly two tails, ii.B= at least twotails, iii.C= the last two tosses are heads(c) List the elements of the following events: i.A, ii.A∪B, iii.A∩B, iv.A∩C

Answers

Answer:

See explanation below

Step-by-step explanation:

Here a coin was tossed three times.

Let H = head &  T = tail

Find the following:

a) The sample space:

Since a coin is tossed thrice, all possible outcome would be:

S = { HHH, HHT, HTH, HTT, TTT, TTH, THH, THT}

b) i) A = Exactly 2 tails: Here exactly 2 tails were recorded.

A = {HTT, TTH, THT}

ii) B = at least two tails: Here 2 or more tails were recorded.

B = {HTT, TTT, TTH, THT}

iii) C = the last two tosses are heads:

C = { HHH, THH}

c) List the elements of the following events:

i) A. This means all outcomes in A

= {HTT, TTH, THT}

ii) A∪B. A union B, means all possible outcomes present in A or B or in both

= {HTT, TTH, THT, TTT}

iii) A∩B. This means all possible outcomes of A that are present in B.

= {HTT, TTH, THT}

iv) A∩C. All outcomes A that are present in B

= {∅}

The sample space of tossing a coin three times consists of eight possible outcomes: HHH, HHT, HTH, THH, TTH, THT, HTT, and TTT. Events A, B, and C can be determined by listing the appropriate outcomes. The intersection and union of events A and B can also be determined.

(a) The sample space, Ω, of tossing a coin three times can be determined by listing all the possible outcomes: HHH, HHT, HTH, THH, TTH, THT, HTT, and TTT.

(b) i. A = {HHT, HTH, THH}

ii. B = {TTT, TTH, THT, HTT, HHT, HTH, THH}

iii. C = {HTH, TTH}

(c) i. A = {HHT, HTH, THH}

ii. A∪B = {HHT, HTH, THH, TTT, TTH, THT, HTT, HHT}

iii. A∩B = {HHT, HTH, THH}

iv. A∩C = {HHT, HTH}

Learn more about Sample-space of coin toss here:

brainly.com/question/32761869

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