MATHEMATICS COLLEGE

Find the slope of the line that contains the following points ( -3 , 7) and (8, -2)

Answers

Answer 1
Answer:

Answer:

-9/11

Step-by-step explanation:

The slope of a line given two points is

m = (y2-y1)/(x2-x1)

   = (-2-7)/(8--3)

    = (-9)/(8+3)

    =-9/11
Answer 2
Answer:

Hope this helped you. :)

Related Questions

Please help! (95 points)
Quick! Please Help Me ASAP!
I need help on this. ive been struggling. TwTlateral areasurface areavolume​
PhD’s in Engineering. The National Science Foundation reports that 70% of the U.S. graduate students who earn PhD degrees in engineering are foreign nationals. Consider the number Y of foreign students in a random sample of 25 engineering students who recently earned their PhD.a) Find the probability that there are exactly 10 foreign students in your sample – use equation for thisb) Find the probability that there are less than or equal to 5 foreign students in your sample andc) Find the mean and standard deviation for Y
Which type of angle is formed by sides of a square?

Please help me understand I am confused

Answers

9514 1404 393

Explanation:

a) The velocity curve is linearly increasing from 0 to 6 m/s over a period of 2 seconds, then linearly decreasing from 6 m/s to 0 over the same period. The acceleration is the rate of change of velocity, so for the first half of the motion the acceleration is a constant (6 m/s)/(2 s) = 3 m/s². Similarly, over the second half of the motion, the acceleration is a constant (-6 m/s)/(2 s) = -3 m/s².

The distance traveled is the integral of the velocity, so the linearly increasing velocity will cause the distance vs. time curve to have a parabolic shape. The shape will likewise be parabolic, but with decreasing slope, as the velocity ramps down to zero. Overall, the distance versus time curve will have an "S" shape.

The motion (position and velocity) will be continuous, but the acceleration will not be. There will be a significant "j.erk" at the 2-second mark where acceleration abruptly changes from increasing the velocity to braking (decreasing the velocity).

__

b) The attachment shows the (given) velocity curve in meters per second and its integral, the position curve, in meters.

The integral in the attached works nicely for machine evaluation. For hand evaluation, it is perhaps best written piecewise:

  s(t)=\begin{cases}\displaystyle\int_0^t{3x}\,dx\qquad\text{for $x\le2$}\n\n\displaystyle6+\int_2^t{(12-3x)}\,dx\qquad\text{for $2<x\le4$}\end{cases}

During the period of time that a local university takes phone-in registrations, calls come inat the rate of one every two minutes.
a. What is the expected number of calls in one hour?
b. What is the probability of three calls in five minutes?
c. What is the probability of no calls in a five-minute period?

Answers

Answer:

a) The expected number of calls in one hour is 30.

b) There is a 21.38% probability of three calls in five minutes.

c) There is an 8.2% probability of no calls in a five minute period.

Step-by-step explanation:

In problems that we only have the mean during a time period can be solved by the Poisson probability distribution.

Poisson probability distribution

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

a. What is the expected number of calls in one hour?

Calls come in at the rate of one each two minutes. There are 60 minutes in one hour. This means that the expected number of calls in one hour is 30.

b. What is the probability of three calls in five minutes?

Calls come in at the rate of one each two minutes. So in five minutes, 2.5 calls are expected, which means that \mu = 2.5. We want to find P(X = 3).

P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)

P(X = 3) = (e^(-2.5)*(2.5)^(3))/((3)!) = 0.2138

There is a 21.38% probability of three calls in five minutes.

c. What is the probability of no calls in a five-minute period?

This is P(X = 0) with \mu = 2.5.

P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)

P(X = 0) = (e^(-2.5)*(2.5)^(0))/((0)!) = 0.0820

There is an 8.2% probability of no calls in a five minute period.

A souvenir mug sells for $8.00 at a hotel gift store. The sales tax on the mug is $0.44.What is the sales tax rate? (Remember, sales tax rate is a percent)

please help with this!!!

Answers

The sale tax rate is 5.5%
Proof : 8 x 5.5% = $8.44

How do you do this question?

Answers

Step-by-step explanation:

K is an upper bound for│f"(x)│on the interval [0, 1], so x ≤ 1.

Sine and cosine have maximums of 1, so an upper bound of │f"(x)│is:

│f"(x)│≤ (76 · 1 + 152 · 1 · 1)

│f"(x)│≤ 228

This is really easy promise

Answers

Answer:

A.) slope= 4 and y intercept= 3

Step-by-step explanation:

y = x4+3

Answer:

y = x4+3

Step-by-step explanation:

look at answer

If the typos are randomly distributed over the 10 pages, find the probability of having a single typo on each page

Answers

1/10 assuming there is are 10 typos in total
Other Questions
At Food Lion, an 8-ounce container of Daisy sour cream is $1.52. Kraft sour cream sells for $2.92 for 12 ounces. Which is the better buy and by how much?
A quality control inspector has drawn a sample of 15 light bulbs from a recent production lot. Suppose that 60% of the bulbs in the lot are defective. What is the expected value of the number of defective bulbs in the sample
What is the length of the hypotenuse of the right angle defined by the points (-3,-1),(1,-1),and (1,2)?A)square root of 3B)square root of 3C) 2 timessquare root of 3D)5
Sum of series 1 +1/3 +1/3².... is?​