Answer:
Explanation:
Pressure on the hydraulic system is expressed as;
Pressure = Force/Area
Given
Force on the fluid = 400N
Area = 0.001m²
Pressure in the fluid = 400/0.001
Pressure in the fluid = 400,000N/m²
1N/m² = 0.001kPa
400,000N/m² = x
x = 400,000 × 0.001
x = 400kPa
Hence the pressure in kPa is 400kPa
b) Using the formula;
Pa = Pb
Fa/Aa = Fb/Ab
Pa = Fb/Ab
Fb = PaAb
Fb = 400,000(0.2)
Fb = 80,000N
Hence the magnitude of the force exerted on the load bearing piston by the hydraulic fluid is 80,000N
In a hydraulic system, a force exerted creates a pressure that is transmitted equally throughout. The induced pressure in the hydraulic system is 400 kPa. By applying the same pressure across the larger piston (0.2 m2), a force of 80,000 N is generated on the load-bearing piston.
The subject of this question is the physics topic of hydraulic systems, specifically how forces and pressure interactions. Use Pascal's principle which states that a change in pressure at any point in an enclosed fluid under equilibrium will be transmitted equally to all parts of the fluid.
a. To find the pressure in kPa induced by the applied pressure, use the formula P=F/A, where P is pressure, F is force and A is area. With the force F = 400 N and area A = 0.001 m2, the induced pressure is P = 400 N / 0.001 m2 = 400,000 Pa or 400 kPa.
b. The force exerted on the load-bearing piston by the hydraulic fluid is calculated by rearranging the formula to F=PxA. So, F = 400kPa x 0.2m2 = 80,000 N. Therefore, the force exerted on the load-bearing piston by the hydraulic fluid is 80,000N.
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Answer:
Point motion will eventually stops due to action of g exactly perpendicular...
Explanation:
If ignoring the air resistance, the magnitude of gravitational acceleration is already strong enough to stops the acceleration. As we know that, the spring constant of a bungee spring cord will be F = -k/x, where x is the stretched length and k is the spring constant of bungee cord. If F = ma = w = mg, the g = -m k/x. Now we can clearly see that the value of g remains constant due to the fluctuating length of the cord as the motion progresses back and forth in SHM say from x1 to x2 and x2 to x1.
Answer:
4611.58 ft/s²
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 32.174 ft/s²
Equation of motion
Magnitude of acceleration while stopping is 4611.58 ft/s²
Answer:
The correct option is D
Explanation:
From the question we are told that
The maximum electric field strength is
The area is
Generally the force the laser applies is mathematically represented as
Here
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Answer:
The mass of the object is approximately 70.79 kilograms
Explanation:
We use Newton's second law to solve this problem. This law states that the net force on an object equals the product of its mass times the acceleration:
Therefore, for this case, since the net force on the object and its acceleration are given, we can use the equation above to solve for the unknown mass:
To solve this problem it is necessary to apply the concepts related to the conservation of energy, through the balance between the work done and its respective transformation from the gravitational potential energy.
Mathematically the conservation of these two energies can be given through
Where,
W = Work
Final gravitational Potential energy
Initial gravitational Potential energy
When the spacecraft of mass m is on the surface of the earth then the energy possessed by it
Where
M = mass of earth
m = Mass of spacecraft
R = Radius of earth
Let the spacecraft is now in an orbit whose attitude is then the energy possessed by the spacecraft is
Work needed to put it in orbit is the difference between the above two
Therefore the work required to launch a spacecraft from the surface of the Eart andplace it ina circularlow earth orbit is
Answer:
The value is
Explanation:
From the question we are told that
The value of the far point is
The distance of the lens to the eye is
Generally
Generally the power spectacle lens needed is mathematically represented as
Here is the object distance which for a near sighted person is
And is the image distance which is evaluated as
=>
=>
So
=>
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