The green house gases in the atmosphere can change the behavior of energy on earth. Thus i agree with this statement.
The green house effect is defined as a process by which the radiations from the sun are absorbed by the green house gases like methane, Chloro fluoro carbons and not reflected back into the space. This makes the surface as insulator and prevents it from freezing.
Due to the increased level of green house gases, the temperature of the earth increases considerably and thereby causes global warming, depletion of ozone layer, smog and air pollution, etc.
It is the natural green house effect which affect the behaviour of heat energy radiated by the sun. The green house gases never let the radiations escape from the earth and increase the surface temperature of earth. This leads to global warming.
Thus green house gases affects the solar energy.
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Answer:
I agree
Explanation:
because the sunlight passes through the atmosphere and is absorbed by earth's surface.
synthesis
decomposition
single displacement
double displacement
SO₃+ H₂SO₄ → H₂SO₄ This reaction is synthesis type of reaction, because that would be combination (synthesis) A + B → AB. Therefore, option A is correct.
There are five basic types of chemical reactions are combination, decomposition, single-replacement, double-replacement, and combustion.
Biochemical reactions are chemical reactions that occur within living things. Metabolism refers to the sum of all biochemical reactions in an organism. Exothermic and endothermic chemical reactions are both part of metabolism.
Hydration is the process of combining water molecules with another substance to form a single, new compound. SO3 is an acidic oxide that reacts with and dissolves in water to form sulfuric acid, H2SO4.
Thus, option A is correct.
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When Americium (Am-241) undergoes alpha decay(He-4) it forms neptunium (Np-237) based on the following pathway:
²⁴¹Am₉₅ → ²³⁷Np₉₃ + ⁴He₂
The energy released in given as:
ΔE = Δmc²
where Δm = mass of products - mass of reactants
= [m(Np-237) + m(He-4)] - [m(Am-241)]
= 237.0482+4.0015-241.0568 = -0.0073 g/mol = -7.3 * 10⁻⁶ kg/mol
ΔE = -7.3*10⁻⁶ kg/mol * (3*10⁸ m/s)² = -5.84*10¹¹ J/mol
(B) H2S
(C) SO3
(D) PCl3
(E) CH2Cl2
(F) NO2
Answer:
D and E
Explanation:
D. PCl3
E. CH2Cl2
Answer:
1) 0.18106 M is the molarity of the resulting solution.
2) 0.823 Molar is the molarity of the solution.
Explanation:
1) Volume of stock solution =
Concentration of stock solution =
Volume of stock solution after dilution =
Concentration of stock solution after dilution =
( dilution )
0.18106 M is the molarity of the resulting solution.
2)
Molarity of the solution is the moles of compound in 1 Liter solutions.
Mass of potassium permanganate = 13.0 g
Molar mass of potassium permangante = 158 g/mol
Volume of the solution = 100.00 mL = 0.100 L ( 1 mL=0.001 L)
0.823 Molar is the molarity of the solution.
To determine the molarity of the resulting solution, we can use the formula M1V1 = M2V2. Plugging in the given values, we find that the molarity of the resulting solution is 0.180 MM.
To determine the molarity of the resulting solution, we need to use the formula:
M1V1 = M2V2
Where M1 is the molarity of the stock solution, V1 is the volume of the stock solution used, M2 is the molarity of the resulting solution, and V2 is the final volume of the resulting solution.
Using the given values, we have:
M1 = 0.823 MM
V1 = 11.00 mL
V2 = 50.00 mL
Substituting these values into the formula, we can find the molarity of the resulting solution.
M2 = (M1 * V1) / V2
Plugging in the values:
M2 = (0.823 MM * 11.00 mL) / 50.00 mL = 0.180 MM
The molarity of the resulting solution is 0.180 MM.
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Answer : The mass of sucrose added to 375 mL of water must be, 10.6 grams.
Explanation :
As we are given that 2.75 m/m percent solution of sucrose. That means, 2.75 grams of sucrose present in 100 grams of solution.
Mass of solution = 100 g
Mass of sucrose = 2.75 g
Mass of water = Mass of solution - Mass of sucrose
Mass of water = 100 g - 2.75 g
Mass of water = 97.25 g
First we have to calculate the mass of water.
Density of water = 1.00 g/mL
Volume of water = 375 mL
Now we have to calculate the mass of sucrose in 375 g of water.
As, 97.25 grams of water contain 2.75 grams of sucrose
So, 375 grams of water contain grams of sucrose
Therefore, the mass of sucrose added to 375 mL of water must be, 10.6 grams.
To make a 2.75% m/m sucrose solution, you need to add approximately 1062 grams of sucrose to 375 mL of water, considering the density of water as 1 g/mL.
To prepare a mass/mass (m/m) percent solution of sucrose, you need to calculate the mass of sucrose (in grams) that needs to be added to 375 mL of water to achieve a 2.75% concentration.
Here's how you can calculate it:
1. Convert the volume of water to grams, considering the density of water:
Density of water ≈ 1 g/mL
Mass of water = Volume of water × Density of water
Mass of water = 375 mL × 1 g/mL = 375 g
2. Determine the desired mass of sucrose as a percentage of the total mass:
Desired m/m percent = 2.75%
3. Calculate the mass of sucrose needed:
Mass of sucrose = (Desired m/m percent / 100) × Total mass
Mass of sucrose = (2.75 / 100) × (375 g + Mass of sucrose)
4. Rearrange the equation to solve for the mass of sucrose:
Mass of sucrose = (2.75 / 100) × (375 g) / (1 - (2.75 / 100))
Now, calculate:
Mass of sucrose = (2.75 / 100) × (375 g) / (1 - 0.0275)
Mass of sucrose ≈ (2.75 / 100) × (375 g) / 0.9725
Mass of sucrose ≈ (2.75 × 375 g) / 100 / 0.9725
Mass of sucrose ≈ (1031.25 g) / 0.9725
Mass of sucrose ≈ 1061.98 g
So, approximately 1062 grams of sucrose must be added to 375 mL of water to prepare a 2.75 m/m percent solution of sucrose.
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