A recipe for beef fajitas uses 5 pounds of beef to make 20 meals. How many pounds of beef are needed to make 80 meals?
Answers
Answer:
20 pounds
Step-by-step explanation:
80/20 =4
5x4=20
Final answer:
The amount of beef needed to make 80 meals, given a ratio of 5 pounds of beef for 20 meals, is 20 pounds.
Explanation:
To get an answer to this question, we first need to establish the ratio of beef needed for a single meal. The recipe suggests that 5 pounds of beef are used to create 20 meals. Thus, the ratio of beef to meals is 5:20. For simplicity, we can reduce this ratio by dividing both sides by 5, resulting in 1:4. This means for every meal, we need a quarter of a pound of beef. The question then asks how many pounds of beef are needed for 80 meals. Since we know a quarter pound of beef is needed for each meal, we can simply multiply the number of meals by 0.25 to get the total pounds of beef required. So, 80 meals x 0.25 pounds = 20 pounds of beef.
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Answers
Answer:
5
Step-by-step explanation:
250-25=225
so then that means...
225 divided by 45=5
5
Help me please
Answers
Answer: z=56
Step-by-step explanation:
Based on the figure, we can determine that 3y+8=68 and 4x=2z. With the knowledge that a trapezoid has 360°, we can first find the value of y to get the angle measures of the top angles. We can then subtract that from 360°.
3y+8=68 [subtract both sides by 8]
3y=60 [divide both sides by 3]
y=20
We now know the value of y is 20, but that is not relevant to solving this problem because we already know that the top angles are 68° each. So, we can subtract that from 360.
360-68-68=224
Now, we know that the bottom 2 angles have to add up to 224. Therefore, we can come up with 2 equations.
Equation 1: 4x=2z
Equation 2: 4x+2z=224
We can manipulate Equation 1 to be . Once we plug that into Equation 2, we can find the value of z.
[multiply]
[add]
[divide both sides by 4]
Now, we know that z=56.
8th math
Pls
Answers
Answers
Answers
Answer:
m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z
or m = 2/3 - (π n_2)/18 for n_2 element Z
Step-by-step explanation:
Solve for m:
-cos(7 m + 2) sin(12 - 18 m) = 0
Multiply both sides by -1:
cos(7 m + 2) sin(12 - 18 m) = 0
Split into two equations:
cos(7 m + 2) = 0 or sin(12 - 18 m) = 0
Take the inverse cosine of both sides:
7 m + 2 = π n_1 + π/2 for n_1 element Z
or sin(12 - 18 m) = 0
Subtract 2 from both sides:
7 m = -2 + π/2 + π n_1 for n_1 element Z
or sin(12 - 18 m) = 0
Divide both sides by 7:
m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z
or sin(12 - 18 m) = 0
Take the inverse sine of both sides:
m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z
or 12 - 18 m = π n_2 for n_2 element Z
Subtract 12 from both sides:
m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z
or -18 m = π n_2 - 12 for n_2 element Z
Divide both sides by -18:
Answer: m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z
or m = 2/3 - (π n_2)/18 for n_2 element Z
Answers
Answer: 50%
Step-by-step explanation:
If you notice the end points we start with odd and end in an even.
There can be a shift that matches evens and odds so 50% evens and 50% odds
From MysticAlanCheng