MATHEMATICS HIGH SCHOOL

Michael is 121212 years older than Brandon. Seventeen years ago, Michael was 444 times as old as Brandon. How old is Michael now?

Answers

Answer 1

Answer:

Let Brandon's age be = b years

Let Michael's age be = m years

As Michael is 12 years older than Brandon, Michael's age, so

$m=b+12$

Seventeen years ago, Michael was 4 times as old as Brandon, so

$m-17=4(b-17)$

$m-17=4b-68$

$m=4b-51$

$m-4b=-51$

Substitute m=b+12

$b+12-4b=-51$

$-3b=-63$

$b=21$

Hence, Brandon's age is 21 years

As m=b+12

$m=21+12$

$m=33$

Hence, Michael's age is 33 years.

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What is 9 times 3/4?

Answers

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Math. :)Question: 1.1W + 2.1 = 5.4
Answer: W = 2.2

Is the answer correct? How do you check the answer?

Thank you in advance!!

Answers

$\sf~W+2.1=5.4$

Subtract 2.1 to both sides:

$\sf~W=3.3$

This is one-step equation.
$W+2.1=5.4 \n W+2.1-2.1=5.4-2.1 \n W=3.3 \n CHECK- \n 3.3+2.1=5.4$

PLEASE HELP!!! WILL GIVE BRAINLIEST!!!

Answers

Angle 1 is 112

Angle 2 is 68

Angle 3 is 90

Angle 4 is 90

Angle 5 is 22

Angle 6 is 158

The relative frequency of green on a spinner is 5/6. How many times would you expect a green in 300 spins?

Answers

5/6*300=250
250 spins

Evaluate the following expression, if possible. 36^((3)/(2))

Answers

Answer:

216

Step-by-step explanation:

The expression in the form $a^(b)/(c)$ can be rewritten as $\sqrt[b]{a^c}$ . Given this, the steps to evaluate the expression are as follows:

Rewrite the expression in the form $\sqrt[b]{a^c}$ :
$36^(3)/(2) =\sqrt[2]{36^3}=√(36^3)$
Evaluate $√(36^3)$ :
$√(36^3) =√(36^2*36)\n =36√(36)\n =36*6\n=216$ The final solution is 216.

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