The distance between (-6,8) and (10,-4) is 20 units.
The shortest distance (length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:
We are given that;
The points (-6,8) and (10,-4)
Now,
To use the formula, you need to plug in the values of x1, y1, x2 and y2 into the formula and simplify. For example, to find the distance between (-6,8) and (10,-4), you can do:
d = (10 - (-6))^2 + (-4 - 8)^2
d = (16)^2 + (-12)^2
d = 256 + 144
d = 400
d = sqrt(400)
d = 20
Therefore, the distance formula the answer will be 20 units.
Learn more about distance between two points here:
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Answer:
use the distance formula you can find it on the net
x + 7
3x - 1
The expression to represent the area of the shaded region is (5x + 2)(x + 7) - (3x - 1)(x + 7). Simplifying the expression gives us 2x^2 + 42x + 7.
To find the area of the shaded region, we need to subtract the area of the smaller rectangle from the area of the larger rectangle. The larger rectangle has a length of (5x + 2) and a width of (x + 7), while the smaller rectangle has a length of (3x - 1) and a width of (x + 7). Therefore, the expression to represent the area of the shaded region is:
(5x + 2)(x + 7) - (3x - 1)(x + 7)
To simplify this expression, we can use the distributive property. First, we simplify the expression in the parentheses:
(5x + 2)(x + 7) - (3x - 1)(x + 7)
(5x^2 + 35x + 2x + 14) - (3x^2 - 7x - x + 7)
Next, we distribute the negative sign:
5x^2 + 35x + 2x + 14 - 3x^2 + 7x + x - 7
Finally, we combine like terms:
2x^2 + 42x + 7
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Answer:
Step-by-step explanation:
To determine what the area of the shaded region is, simply find the area of the large rectangle and subtract the product from the smaller one.
Since they are polynomials. Multiply one binomial to the other and first obtain the product, before subtracting the product of the smaller rectangle.
(5x + 2)(3x - 1) - (x)(x + 7)
15x^2 - 5x + 6x - 2 - x^2 - 7
14x^2 + x - 9.
I believe this would be the solution in standard form.
B. 2/5
C. 42/48
D. 245/1152