If yes, provide the correct Triangle Congruence Postulate or Theorem and a
congruence statement.
If no, justify your answer.
Answer:
Yes.
∆CAB ≅ ∆XYZ by AAS Congruence Theorem.
Step-by-step explanation:
There's enough information provided in the diagram above for us to prove that ∆CAB is congruent to ∆XYZ.
From the diagram, we cam observe the following:
<A ≅ <Y
<B ≅ <Z
side CA ≅ XY
Using the Angle-Angle-Side (AAS) Congruence Theorem, since two angles, <A and <B, and a non-included side, CA, in ∆CAB are congruent to two the corresponding angles, <X and <Z, and a non-included side, XY, in ∆XYZ, then ∆CAB is congruent to ∆XYZ.
Answer: He cut 6 slices of bread.
Step-by-step explanation:
Given : Jared ate of a loaf of bread.
Then , the reaming portion of the bread will be .
The size of each slice = of a bread.
N ow , the number of slices he cut the remaining portion =
Hence, the number of slices of bread he cut = 6.
Answer:
6:1
Step-by-step explanation:
48:( 4+4 )
= 48:8
= 6:1
ANSWE,LET two numbers be A and B then
A+B=52
A-B=14....linear equation in 2 variable
adding 2 eqns
2A=66... dividing both side by 2
A=33
and put A=33 in eqn A+B=52
B=52-33
B=19.
SO. LARGER NUMBER=33
Smaller number=19
Answer:
0.4 ; 0.6125
Step-by-step explanation:
Given the following :
Bag 1 : 75 red ; 25 blue
Bag 2: 60 red ; 40 blue
Bag 3: 45 red ; 55 blue
Probability = (required outcome / Total possible outcomes)
A) since the probability of choosing each bag is equal :
BAG A:
P(choosing bag A) = 1 / total number of bags = 1/3 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100
HENCE, choosing a blue marble from bag A : = (1/3 × 75/100) = 25/300
BAG B:
P(choosing bag B) = 1/3 ;
P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100
HENCE, choosing a blue marble from bag A : = (1/3 × 40/100) = 40/300
BAG C:
P(choosing bag C) = 1/3
P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100
HENCE, choosing a blue marble from bag A : = (1/3 × 55/100) = 55/300
= (25/300) × (40/300) × (55/300) = (25 + 40 + 55)/300 = 120/300 = 0.4
2) What is the probability that the marble is blue when the first bag is chosen with probability 0.5 and other bags with equal probability each?
BAG A:
P(choosing bag A) = 0.5 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100
HENCE, choosing a blue marble from bag A : = (0.5 × 75/100) = (0.5 * 0.75) = 0.375
BAG B:
P(choosing bag B) = (1-0.5) / 2 = 0.25 ;
P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100
HENCE, choosing a blue marble from bag A : = (0.25 × 40/100) = (0.25 × 0.4) = 0.1
BAG C:
P(choosing bag C) = (1 - (0.5+0.25)) = 0.25
P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100
HENCE, choosing a blue marble from bag A : = (0.25 × 55/100) = 0.25 × 0.55 = 0.1375
= 0.1375 + 0.1 + 0.375 = 0.6125