What is the difference between (4,4) and (1,-3)

Answers

Answer 1

Answer:

Answer:

7/3

Step-by-step explanation:

If I solved it correctly, you use y2-y1 / x2-x1. From here you get -3-4/1-4=-7/-3 which when you divide equals 7/3. LMK IF its wrong and ill figure it out champ!

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The radius of the large sphere is double the radius of thesmall sphere.
How many times is the volume of the large sphere than the
small sphere?
2
VX
O 4
O 6
O 8

Answers

Answer:

4 times as great

Step-by-step explanation:

Compute the two different volumes and then compare them.

Smaller sphere: V = (4/3) · π ·r²

Larger sphere: V = (4/3) · π · (2r)² = (4/3) · π · 4 · r²

Comparing these, one sees immediately that the volume of the larger sphere is 4 times as great as that of the smaller sphere.

ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.

Answers

Answer:

Step-by-step explanation:

When an equation shifts down, you simply subtract the amount of units and when it shifts up, you add the amount of units so since it is 2 units down, it is -2

Answer:

Step-by-step explanation:

It is D because 'moving it down 2 spaces' has to do with the y-axis. If you move a line 2 spaces down then you are moving it down by -2.

Does anyone know the answer???

Answers

Answer:

Step-by-step explanation:

Researchers suspect that the average number of units earned per semester by college students is rising. A researcher at Calendula College wishes to estimate the number of units earned by students during the spring semester at Calendula. To do so, he randomly selects 100 student transcripts and records the number of units each student earned in the spring term. He found that the average number of semester units completed was 12.96 units per student. Identify the population of interest to the researcher.

Answers

Answer:

All Calendula College students enrolled in the spring.

Step-by-step explanation:

A researcher at Calendula College wishes to estimate the number of units earned by students during the spring semester at Calendula.

To do so, he randomly selects 100 student transcripts from among all Calendula College students enrolled in the spring and records the number of units each student earned in the spring term.

NEED ASAPWhat is the product?
а-3
11
5
15а а-3
о
о
Cul —
за
о за
O3

Answers

The product of the given expressions is (1/3a). therefore, option (1/3a) is correct.

To find the product of the two expressions:

(а - 3) / (15a) * (5 / (a - 3))

First, notice that (a - 3) appears in both the numerator and the denominator, and these terms will cancel out, leaving:

(5 / 15a)

Now, you can simplify this fraction:

5 / 15a = (1/3a)

So, the product of the given expressions is:

(а - 3) / (15a) * (5 / (a - 3)) = (1/3a)

for such more question on expressions

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Answer:

1/3a

Step-by-step explanation:

$((a - 3))/(15a) * (5)/((a - 3)) = (5)/(15a) = (1)/(3a)$

You are the operations manager for an airline and you are considering a higher fare level for passengers in aisle seats. How many randomly selected air passengers must you survey? Assume that you want to be 99% confident that the sample percentage is within 5.5 percentage points of the true population percentage. Complete parts (a) and (b) below. a. Assume that nothing is known about the percentage of passengers who prefer aisle seats. nequals 549 (Round up to the nearest integer.) b. Assume that a prior survey suggests that about 34% of air passengers prefer an aisle seat. nequals nothing (Round up to the nearest integer.)

Answers

Answer:

a) $n=(0.5(1-0.5))/(((0.055)/(2.58))^2)=550.116$

And rounded up we have that n=551

b) $n=(0.34(1-0.34))/(((0.055)/(2.58))^2)=493.78$

And rounded up we have that n=494

Step-by-step explanation:

Previous concept

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{(p(1-p))/(n)})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.05$ . And the critical value would be given by:

$z_(\alpha/2)=-2.58, t_(1-\alpha/2)=2.58$

Part a

The margin of error for the proportion interval is given by this formula:

$ME=z_(\alpha/2)\sqrt{(\hat p (1-\hat p))/(n)}$ (a)

And on this case we have that $ME =\pm 0.05$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\hat p (1-\hat p))/(((ME)/(z))^2)$ (b)

We can assume that $\hat p =0.5$ since we don't know prior info. And replacing into equation (b) the values from part a we got:

$n=(0.5(1-0.5))/(((0.055)/(2.58))^2)=550.116$

And rounded up we have that n=551

Part b

$n=(0.34(1-0.34))/(((0.055)/(2.58))^2)=493.78$

And rounded up we have that n=494

Final answer:

To determine the required sample size for the survey, we can use a sample size formula based on the desired confidence level and margin of error. If nothing is known about the passenger preferences, a sample size of 549 would be needed. If a prior survey suggests a certain proportion, the sample size can be calculated using the known proportion.

Explanation:

In order to determine the number of randomly selected air passengers that must be surveyed, we need to calculate the required sample size for a desired confidence level and margin of error.

a. If nothing is known about the percentage of passengers who prefer aisle seats, we can use a sample size formula given by n = (Z^2 * p * q) / E^2, where Z is the z-score corresponding to the desired confidence level, p and q are the estimated proportions for aisle seat preference and non-aisle seat preference respectively, and E is the desired margin of error. Since a confidence level of 99% and a margin of error of 5.5% are specified, we can round up the sample size to 549.

b. If a prior survey suggests that about 34% of air passengers prefer an aisle seat, we can use the same sample size formula but with the known proportion p = 0.34. We do not have information about the non-aisle seat preference, so we cannot determine the required sample size.

Learn more about Sample size calculation here:

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