Answer:
Step-by-step explanation:
Area of a square = Length * Length
Given
Length of garden = 7.4feet
Area of the square = 7.4 * 7.4
Area of the square = 54.76 ft²
Hence the area of the garden is 54.76 ft²
If I'm reading the question right, you have
and you have to find
The limits exist if the limits from either side exist. We have
and
The function f(x) is a piecewise function. The limit as x approaches 5 equals 2 and the limit as x approaches 6 does not exist as the values from both sides are not the same.
The function f(x) given is a piecewise function which is defined differently on different intervals of x.
First let's graph these three conditions:
Next, we'll find the specified limits:
#SPJ11
if g=8,what is the value of the expression g/2+3
Answer:
7
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Step-by-step explanation:
Step 1: Define
g/2 + 3
g = 8
Step 2: Evaluate
Answer:
if g is equals to 8 therefore g/2 +3 will be expressed as 8/2 +3= whuch is equals to 4
Answer:
£43.23
Step-by-step explanation:
8645 cans divided by 72 per kilo is 120.069 kilos of cans
120.069 kilos times 0.36 pounds
Rounded up to 43.23
Answer:
Well It would about 1/10000000 if your talking about all colors, but its not specified how many blue regions other colored regions there are so I cant tell you without knowing.
Step-by-step explanation:
Just Take the amount of regions then put it under the amount of Blue regions there are then look up on a browser, Ex: What is 2/3 into a percent: 66.6 percent, And you have your answer :)
Answer:
15/17
Step-by-step explanation:
The exponential function representing the bacteria population after t hours is f(t) = 2000 * e^(ln(0.5)/3 * t).
To find the exponential function that represents the size of the bacteria population after t hours, we can use the formula N = N0 * e^(kt), where N0 is the initial population, e is Euler's number (approximately 2.71828), k is the growth/decay constant, and t is the time in hours.
In this case, the initial population N0 is 2,000 and the population after 3 hours is 1,000. Plugging these values into the formula, we get:
N = 2000 * e^(3k) = 1000
Solving for k, we find k = ln(0.5)/3. Therefore, the exponential function representing the bacteria population after t hours is f(t) = 2000 * e^(ln(0.5)/3 * t).
#SPJ3
The exponential decay function representing the bacteria population after t hours is f(t) = 2000 × 0.5^(t/3), where t is the number of hours passed.
The student has observed a population of bacteria decreasing from 2,000 to 1,000 over three hours and seeks an exponential function to model the decay of the population over time, expressed as f(t). Since the population is halving every three hours, we can represent this with the function f(t) = 2000 × 0.5^(t/3), where 2000 is the initial population, 0.5 represents the halving, and t is the time in hours. The exponent (t/3) is used because the halving occurs every three hours.
#SPJ2
y=40- 3x-3
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