MATHEMATICS HIGH SCHOOL

What is 8/5+ (-1/3)

Answers

Answer 1

Answer:

Answer:

19/15

Step-by-step explanation:

Answer 2

Answer: 19/15 is the answer

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Solve for Zeros by factoring
5x^2 + 13x - 6

Answers

$5x^2+13x-6$

Break the expression into groups:

$=(5x^2-2x)+(15x-6)$

Factor out x from : $5x^2-2x = x(5x-2)$

Factor out 3 from : $15x-6=3(5x-2)$

$=x(5x-2)+3(5x-2)$

Factor out common term $(5x-2)$

$= (5x-2)(x+3)$

hope this helps!

Describe how the formulas for a cone, cylinder and pyramid are derived. What are the similarities between the volume of a cone and pyramid?

Answers

the similarities

Vcylinder=hpir^2
Vcone=(1/3)hpir^2

Vpyramid=(1/3)hlw

notice that the cylinder has a circle base and circle top
cone tapers
when that happens, the cone is 1/3 of the whole

so the pyrmid is 1/3 the volume of a shape with same base area and same height

Simplify 2 over squareroot 5

Answers

Square Root cannot be in the Denominator, therefore:

2 / √5
2 × √5 / √5 × √5
2√5 / 5

Hope this helps!

the volume of a sphere is 950 cubic inches. use the formula for the volume of a sphere, V= 4/3(3.14)(r)ratical 3, to find the radius r to the nearest tenth of an inch.

Answers

Given:
Volume = 950 cubic inches

V = 4/3 π r³ ; where π = 3.14

950 in³ = 4/3 * 3.14 * r³
950 in³ = 4.19 * r³
950 in³ ÷ 4.19 = r³
226.73 in³ = r³
∛226.73 in³ = ∛r³
6.09 = r

The radius is 6.09 or 6.10 inches.

How do i find the surface area?

Answers

Surface area is what it seems to be. All of the area of the solid's faces together. Like a cube, just find the areas of all of the squares that make the cube then add them together.

You are driving home on a weekend from school at 55 mi/h for 110 miles. it then starts to snow and you slow to 35 mi/h. you arrive home after driving 4 hours and 15 minutes. how far is your hometown from school

Answers

The distance between hometown and school is 188.75 miles.

Given that, the person drive 110 miles at 55 miles/hour.

Average speed is calculated by dividing a quantity by the time required to obtain that quantity. Meters per second is the SI unit of speed. The formula $S = (d)/(t)$ , where S is the average speed, d is the total distance, and t is the total time, is used to determine average speed.

Due to snow, speed is slow down to 35 miles/hour.

Let x miles be travelled with 35 miles/hour.

Total time taken to travel is 4 hours and 15 minutes.

Here, $T_1=(110)/(55)$ and $T_2=(x)/(35)$

Now, $T=T_1+T_2$

$(110)/(55)+(x)/(35)=4(15)/(60)$

$((110*7+x*11))/(385)=4(1)/(4)$

$((770+11x))/(385)=(17)/(4)$

$4(770+11x)=385*17$

$3080+44x=6545$

$44x=6545-3080$

$44x=3465$

$x=78.75$ miles

Total distance = 110+78.75

= 188.75 miles

Therefore, the distance between hometown and school is 188.75 miles.

Learn more about the average speed here:

brainly.com/question/9834403.

#SPJ12

Final answer:

The total distance from school to the student's hometown is calculated as the sum of distances covered at different speeds. The student spends 2 hours at 55 mi/h, covering 110 miles, and then 2.25 hours at 35 mi/h, covering 78.75 miles, making up a total of 188.75 miles.

Explanation:

The question pertains to the concepts of distance, speed and time in mathematics. In this scenario, the student drives at a speed of 55 mi/h for 110 miles and then slows down due to snowfall and drives at 35 mi/h. From this information, we can calculate the time spent at each speed.

Firstly, since Speed = Distance / Time, we can rearrange to find Time = Distance / Speed. For the first stretch of the journey, the time is 110 miles / 55 mi/h = 2 hours.

It is given that the total journey takes 4 hours and 15 minutes which is equivalent to 4.25 hours. So, the time spent driving at 35 mi/h is 4.25 hours (total trip time) - 2 hours (first stretch) = 2.25 hours.

The distance covered when it was snowing can be found by multiplying this time by the slower speed: 35 mi/h * 2.25 h = 78.75 miles.

Therefore, the total distance from school to the student's hometown is the sum of the distance traveled at each speed: 110 miles (at 55 mi/h) + 78.75 miles (at 35 mi/h) = 188.75 miles.