Answer: In addition to building texture, starches are used to contribute stability to food products. This often takes the form of holding water. As previously mentioned, gelatinized starch molecules tend to reassociate with one another.
In the periodic table,the The +3 oxidation state is characteristic of the actinides. All actinides are radioactive.The actinides are silvery and chemically reactive.
Periodic table is a tabular arrangement of elements in the form of a table. In the periodic table, elements are arranged according to the modern periodic law which states that the properties of elements are a periodic function of their atomic numbers.
It is called as periodic because properties repeat after regular intervals of atomic numbers . It is a tabular arrangement consisting of seven horizontal rows called periods and eighteen vertical columns called groups.
Elements present in the same group have same number of valence electrons and hence have similar properties while elements present in the same period show gradual variation in properties due to addition of one electron for each successive element in a period.
Learn more about periodic table,here:
#SPJ2
Answer:
The +3 oxidation state is characteristic of the actinides.
All actinides are radioactive.
Cerium (Ce) rnakes 100th in abundance (by mass %).
The actinides are silvery and chemically reactive.
Answer: The balanced chemical equation for the reaction of phosphorus trichloride with water is written below.
Explanation:
A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.
The balanced chemical equation for the reaction of phosphorus trichloride with water follows:
By Stoichiometry of the reaction:
1 mole of liquid phosphorus trichloride reacts with 3 moles of water to produce 1 mole of aqueous phosphorus acid and 3 moles of aqueous hydrochloric acid.
Hence, the balanced chemical equation for the reaction of phosphorus trichloride with water is written above.
Hey there!:
I'll balance it:
PCl3 + H2O ---> H3PO3 + HCl
* PCl3 (l )+ 3 H2O (l)--->H3PO3(aq) +3 HCl(aq)
Hope that helps!
a hurricane
a volcanic eruption
a landslide
an earthquake
Answer: I believe the answer is an earthquake.
Explanation: Sorry If I am wrong!
Answer:
earthquake
Explanation:
I took the k12 test
O A experiment
OB. observational research
Oc.
survey
OD
case study
Answer:
experiment is the answer
Answer:
504.57 K.
Explanation:
From the question given above, the following data were obtained:
Number of mole (n) = 6.81 moles
Pressure (P) = 2.99 atm
Volume (V) = 94.35 L
Gas constant (R) = 0.0821 atm.L/Kmol
Temperature (T) =.?
Using the ideal gas equation, the temperature of the ideal gas can be obtained as follow:
PV = nRT
2.99 × 94.35 = 6.81 × 0.0821 × T
282.1065 = 0.559101 × T
Divide both side by 0.559101
T = 282.1065 / 0.559101
T = 504.57 K.
Thus, the temperature of the ideal gas is 504.57 K.
i) Before adding NaOH
ii) After adding 24.00 mL NaOH
Answer:
i) pH = 0.6990
ii) pH = 2.389
Explanation:
i) Before adding aqueous NaOH, there are 25.00 mL of 0.2000 M HCl. HCl reacts with the water in the aqueous solution as follows:
HCl + H₂O ⇒ H₃O⁺ + Cl⁻
The HCl and H₃O⁺ are related to each other through a 1:1 molar ratio, so the concentration of H₃O⁺ is equal to the HCl concentration.
The pH is related to the hydronium ion concentration as follows:
pH = -log([H₃O⁺]) = -log(0.2000) = 0.699
ii) Addition of NaOH causes the following reaction:
H₃O⁺ + NaOH ⇒ 2H₂O + Na⁺
The H₃O⁺ and NaOH react in a 1:1 molar ratio. The amount of NaOH added is calculated:
n = CV = (0.2000 mol/L)(24.00 mL) = 4.800 mmol NaOH
Thus, 4.800 mmol of H₃O⁺ were neutralized.
The initial amount of H₃O⁺ present was:
n = CV = (0.2000 mol/L)(25.00 mL) = 5.000 mmol H₃O⁺
The amount of H₃O⁺ that remains after addition of NaOH is:
(5.000 mmol) - (4.800 mmol) = 0.2000 mmol
The concentration of H₃O⁺ is the amount of H₃O⁺ divided by the total volume. The total volume is (25.00 mL) + (24.00 mL ) = 49.00 mL
C = n/V = (0.2000 mmol) / (49.00 mL) = 0.004082 M
The pH is finally calculated:
pH = -log([H₃O⁺]) = -log(0.004082) = 2.389