The layers of the Earth, from lowest to highest density, are the Continental crust, Oceanic crust, Asthenosphere, Outer core, and Inner core.
The layers of the Earth can be ordered by density from lowest to highest as follows: Continental crust, Oceanic crust, Asthenosphere, Outer core, and Inner core.
The Continental crust being the top-most layer, has the lowest density, ranging between 2.2 to 2.9 g/cm³. Below that, the Oceanic crust has a slightly greater density at about 3.0 g/cm³.
Below these crust layers is the Asthenosphere, part of the upper mantle, with a density ranging between 3.2 and 3.3 g/cm³.
The denser Outer core lies beneath with a density ranging from 9.9 to 12.2 g/cm³. At the core of the Earth, the inner core has the highest density, ranging from 12.6 to 13.0 g/cm³.
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Answer:
the first is the inner core second is outer core third oceanic cruat fourth contenental crust fifth asthenosphere
a. Water
b. Hydrogen
c. Gold
d. Table salt
Water for sure.
100 degrees Celsius is 212 degrees Fahrenheit
0 degrees Celsius is 32 degrees Fahrenheit.
Be sure to remember that for future events! :)
The best name for the compound is DINITROGEN TRIOXIDE.
Each chemical compound is always represented by a chemical symbol, which shows the ratio at which each atom of the elements of the compound are combine together and this is often used in naming the compound. Looking at the compound given in the question, the compound is made up of two atoms of nitrogen and three atoms of oxygen and this fact was used in naming the compound. In naming chemical compounds, 'Di' stands for 2 while 'Tri' stands for 3. Since there are two nitrogen and three oxygen atoms in the compound, that was why it was named dinitrogen trioxide.
Answer: A) 149.10 g/mol
Explanation:
First, I list what I know, which are the molar masses of N, H, P, and O:
N = 14.01 g/mol
H = 1.01 g/mol
P = 30.97 g/mol
O = 15.99 g/mol
Now, I determine how many molecules of N, H, P, and O there are, starting with (NH₄)₃:
With just NH₄, there would be 1 N and 4 H, but since there are () around it with a subscript of 3, we multiply 3 by both N and H₄, so:
1*3 = 3 N
1*12 = 12 H
Now, we look at PO₄:
The subscript of 3 is before PO₄, so we do not apply that to PO₄:
1 P
4 O
Now, we know the molar masses and number of each of the elements, so we can determine the molar mass of the entire compound.
First, I calculate the total molar masses of each of the elements by multiplying the number of molecules of the element by the element's molar mass:
3 N = 3*14.01 g/mol = 42.03 g/mol
12 H = 12*1.01 g/mol = 12.12 g/mol
1 P = 1*30.97 g/mol = 30.97 g/mol
4 O = 4*15.99 g/mol = 63.96 g/mol
Then, I calculate the total molar mass of the compound by adding the total molar masses of each of the elements together:
42.03 + 12.12 + 30.97 + 63.96 = 149.08 g/mol
I probably used slightly different approximations of the molar masses of each element, but my answer is closest to choice A) 149.10 g/mol.
So, if there are no () around a compound, like PO₄, the subscript only applies to the element it's attached to, so there are 4 molecules of O and only 1 molecule of P.
If there are () around a compound with a subscript, like (NH₄)₃, the subscript after the () gets applied to each element inside the ().
I hope this helps! :)
The molar mass of the compound (NH₄)₃PO₄ is calculated by adding up the molar masses of all its constituent elements. The calculated molar mass is approximately 149.09 g/mol, which corresponds to answer choice (A) 149.10 g/mol.
To calculate the molar mass of a compound, you multiply the quantity of each element by its atomic mass and then sum them all up. The formula (NH₄)₃PO₄ contains Nitrogen (N), Hydrogen (H), Phosphorous (P), and Oxygen (O). The atomic masses of these elements are approximately 14.01 g/mol, 1.01 g/mol, 30.97 g/mol, and 16.00 g/mol respectively. So for the compound (NH₄)ᵣPO₄, the molar mass would be as follows:
(3*N) + (12*H) + (1*P) + (4*O) = (3*14.01) + (12*1.01) + 30.97 + (4*16.00) = 149.09 g/mol approximately
Therefore, the closest answer choice to the correct molar mass is (A) 149.10 g/mol.
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Answer:
1.3005 M
Explanation:
Given that:
Mass of NaCl = 76 g
Molar mass of NaCl = 58.44 g/mol
The formula for the calculation of moles is shown below:
Thus,
Given that volume = 1 L
Considering:
Molarity = 1.3005 M
Answer: The water is highly corrosive when the saturation index < - 0.5 and
> 0.5
Explanation:
If the saturation index for a pool measures the balance between the acid level and the amount of minerals in pool water. Considering its balanced water has an index value of 0.
The water is highly corrosive when the saturation index < - 0.5 and
> 0.5
The attachment below shows the calculations.