MATHEMATICS HIGH SCHOOL

10x + 5x – 3 = 2(2x – 1)

Answers

Answer 1
Answer:

Answer:

The answer is x = 1/11

Step-by-step explanation:

hope this helps

10x + 5x – 3 = 2(2x – 1)

10x+5x-3=4x-2

15x-4x=-2+3

11x=1

To find x divide both sides by 11

11x/11=1/11

x= 1/11
Answer 2
Answer:

Answer:

(1)/(11) or 0.0909090909090

Step-by-step explanation:

Add similar elements: 15x-3=2(2x-1)

Expand 2(2x-1): 4x-2

Add 3 to both sides

Simplify 15x=4x+1

Subtract 4x from both sides

Simplify 11x=1

Divide both sides by 11

Simplify (1)/(11) or 0.0909090909090

:)Hope You Enjoy:)

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Select the proper placement for parentheses to speed up the addition for the expression 4 + 6 + 5 A. (5 + 6) + 4   B. (4 + 6) + 5   C. 4 + (6 + 5)   D. (5 + 4) + 6

Answers

im guessing that by making 10 it will speed up the addition process so it should be 
B since (6+4) = 10 then +5 =15
the answer is B becuase 6+4=10 10+5=15

Question 37 of 55 James buys headphones that cost $10.00. He pays 6% sales tax. How much does he pay for the headphones with tax? A. $11.60
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Answers

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4x+11<23 solve this equation

Answers

4x + 11 < 23

      - 11  - 11

4x < 12

4x/4 < 12/4

x < 3

Issa jogged 2/3 of the way home from school .Then he was tired ,so he walked the remaining 3,200 m how many kilometers did he travel from school to home

Answers

Answer:

9.6 km

Step-by-step explanation:

Issa jogged 2/3 of the way home from school.

Then he was tired, so he walked the remaining 3200 m.

In other words, the remaining 3200 m is 1/3 of the way from school to home.

Let the distance from school to home be x. Therefore:

(1)/(3) * x = 3200\n\n=> x = 3200 * 3 \n\nx = 9600 m

Therefore, from school to home he traveled 9600 m.

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3t<-15 a. t<-5 b. t>-5 c. t<-45 d. t>-45

Answers

3t<-15 solve for t

divide both sides by 3
3t/3 < -15/3

Simplify
t < -5

Anser is a. t<-5
If 3t < -15 all you need to do is divide by 3 on both sides, 

t < -5

PLEASE HELP Polynomial Graph Studies Polynomials are great functions to use for modeling real-world scenarios where different intervals of increase and decrease happen. But polynomial equations and graphs can be trickier to work with than other function types. In mathematical modeling, we often create an equation to summarize data and make predictions for information not shown on the original display. In this activity, you’ll create an equation to fit this graph of a polynomial function. Part A Describe the type of function shown in the graph. Part B What are the standard form and the factored form of the function? Part C What are the zeros of the function? Part D Use the zeros to find all of the linear factors of the polynomial function. Part E Write the equation of the graphed function f(x), where a is the leading coefficient. Use the factors found in part D. Express the function as the product of its leading coefficient and the expanded form of the equation in standard form. Part F Use the y-intercept of the graph and your equation from part E to calculate the value of a. Part G Given what you found in all of the previous parts, write the equation for the function shown in the graph.

Answers

Answer:

Here's what I get  

Step-by-step explanation:

Part A

The graph shows a polynomial of odd degree. It is probably a third-degree polynomial — a cubic equation.

Part B

The standard form of a cubic equation is

y = ax³ + bx² + cx + d

The factored form of a cubic equation is

y = a(x - b₁)(x² + b₂x + b₃)

If you can factor the quadratic, the factored form becomes

y = a(x - c₁)(x - c₂)(x - c₃)

Part C

The zeros of the function are at x = -25, x = - 15, and x = 15.

Part D

The linear factors of the function are x + 25, x + 15, and x - 15.

Part E

y = a(x + 25)(x + 15)(x - 15) = a(x + 25)(x² - 225)  

y = a(x³ + 25x² - 225x - 5625)

Part F

When x = 0, y = 1.

1 = a[0³ +25(0)² - 225(0) - 5625] = a(0 + 0 - 0 -5625) = -5625a

a = -1/5625

Part G

y = -(1)/(5625)( x^(3) + 25x^(2) - 225x - 5625)\n\ny = \mathbf{ -(1)/(5625) x^(3) - (1)/(225)x^(2) + (1)/(25) x + 1}

Answer

Actually, the answer should be -0.0007(x+20)(x+5)(x-15)

Step-by-step explanation:

This is continuing off of the previous answer

PART C

The zeros should be (15,0), (-5,0), and (-20,0)

PART D

x - 15, x + 5, and x + 20

PART E

a(x - 15)(x + 5)(x + 20)

Standard: a(x^(3) + 10x^(2) -275x-1500)

PART F

The y-intercept is at (0,1), so we replace the x's with 0:

1 =[(0)x^(3) +10(0)x^(2) -275(0)-1500] and this gives us (0+0-0-1500) which also equals -1500

Then we do (1)/(-1500) which gives us -0.0006 repeating which rounds to -0.0007

a= -0.0007

PART G

Just place the numbers where they should go and your answer is

y =-0.0007(x + 20)(x + 5)(x - 15)  

the placement for (x + 20) (x + 5) and (x - 15) doesn't matter as long as they are behind -0.0007
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