64
80 80
thats how you havw to put it
Answer:
80/100 is 80%
Step-by-step explanation:
2) x= -1 and x = 2
3) x= 1 and x = -2
4) x = 1 and x = 2
Answer:
third option
Step-by-step explanation:
Given
f(x) =
The denominator cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.
solve x² + x - 2 = 0 ← in standard form
(x + 2)(x - 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
x - 1 = 0 ⇒ x = 1
The vertical asymptotes are x = 1 and x = - 2
The numerical length of JK is 21 units.
Given that, point J is on line segment IK.
We need to determine the numerical length of JK.
In geometry, a line segment is a part of a line that is bounded by two distinctend points and contains every point on the line that is between its endpoints.
Given JK=x+6, IJ=9, and IK=2x.
Now, IK=JK+IJ
⇒2x=x+6+9
⇒2x=x+15
⇒x=15
Now, JK=x+6=21
Therefore, the numerical length of JK is 21 units.
To learn more about the line segment visit:
brainly.com/question/25727583.
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The distance of the line segment is solved and length of JK = 21 units.
Given data:
Since point J is on the line segment IK, the sum of lengths JK and IJ should be equal to the length of the whole line segment IK.
IJ + JK = IK
IJ = 9
IK = 2x
Now, substitute the values and solve for JK:
9 + JK = 2x
To find JK, we need to isolate it on one side of the equation. Subtract 9 from both sides:
JK = 2x - 9
Now, we are also given that JK = x + 6, so we can set these two expressions equal to each other:
2x - 9 = x + 6
Subtract x from both sides:
2x - x = 6 + 9
x = 15
Now, substitute the value of x back into the expression for JK:
JK = 2(15) - 9
JK = 30 - 9
JK = 21
Hence, the numerical length of JK is 21 units.
To learn more about distance between 2 points, refer:
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Answer:
+9or -9 is the answer ☺️ you
Answer:
y will be equal to 0, 9, or 1
(y=0, 9, 1)