The mass of a neutron is approximately 10,000 times the mass of an electron.
The mass of a neutron is approximately 20,000 times the mass of an electron.
The mass of a neutron is approximately 1,000 times the mass of an electron.
Answer:
The mass of a neutron is approximately 2,000 times the mass of an electron
Step-by-step explanation:
= 2 × 10⁻²⁴ / (9 × 10⁻²⁸)
= (2/9) × 10⁻²⁴ ⁻ ⁻²⁸
= (2/9) × 10⁻²⁴ ⁺ ²⁸
≈ 0.2222... × 10²⁸ ⁻ ²⁴
≈ 0.2222 × 10⁴
≈ 2222
This is approximately 2000 times.
Answer:
Step-by-step explanation:
The equation for Pablo's order is given as 6T+2D=9 or 6T+2D-9=0
While the equation for Jasmine's order is given as 4T+2D=7 or 4T+2D-7=0
Subtracting Jasmine's equation from Pablo's
6T+2D-9-(4T+2D-7)=0
This gives us
6T+2D-9-4T-2D+7=0
The reduces to
2T-2=0
Dividing all through by 2 gives
T-1=0
Therefore
T=1
Substituting the value for T into any of the equations of either Pablo and Jasmine
Using Pablo's
6T+2D=9
6(1)+2D=9
2D=9-6
2D=3
There D= 3/2
Answer: ( l + w)
your welcome
Answer:
Hallie can use the equation p = 4l + 4w + 4h to determine the sum of the lengths of the edges of a rectangular prism. She begins to solve the equation for h but runs out of time. Her partial work is shown below: p = 4l + 4w + 4h = l + w + h h = l+w
Answer:
y = 9/8 for part one of solving y in this equation .
Step-by-step explanation:
Answer:
x= (√2y+6/2)-1
Step-by-step explanation:
Swap sides so that all variable terms are on the left hand side.
2x^2+4x−1=y
Subtract y from both sides.
2x^2+4x−1−y=0
Using quadratics formula:
x=-4±√4²-4*2(y-1)/2*2
x= −4±2√2y+6/4
Next solve the equation by using either ± = subtraction or addition
I am using ± = addition. This means I add -4 to 2. From there I simplify equation.
x= (√2y+6/2)-1
Not sure if this means to find x, but I think this is what it would be.
The number of students who attended the museum opening is 80.
A linear equation is an algebraic equation of degree one. In general, the variable or the variables(in the case of a linear equation in two variables) the variables are x and y.
Given, A group of 100 people, some students and some faculty, attended a museum opening.
Assuming no. of students to be x and no. of faculty to be y.
∴ x + y = 100...(i)
Each student paid $10 per person for entrance to the museum and each of the faculty paid $25 per person for entrance and the total cost is $1300.
∴ 10x + 25y = 1300...(ii)
Now multiplying eqn(i) by 10 we get 10x + 10y = 1000...(iii)
Subtracting eqn(iii) from eqn(ii) we get 15y = 300 ⇒ y = 20 and substitting value of y in eqn(iii) we get x = 80.
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STUDENTS X 10
FACULTY 100-X 25
10X + 25(100-X) = 1300
10X + 2500 -25X = 1300
10X - 25X = -2500 + 1300
-15X = -1200
15X = 1200
X = 1200/15
X = 80 STUDENTS <--------SOLUTION