Indicar tipo de unión química que presentan los siguientes compuestos. Realizar a representación de Lewis, molecular o iónica, según corresponda: a-CH4 b-SrO c-HBr d-NH3 e-Cl2O f-Li2O g-CO2 h-MgCl2

Answers

Answer 1
Answer:

Answer:

Explanation:

a. CH₄- Covalent bonding(ligação covalente)

b. SrO- ionic bonding (ligação iônica)

c. HBr- Polar Covalent bonding (ligação covalente polar)

d. NH₃ - covalent bonding(ligação covalente)

e. Cl₂O - Covalent bonding (ligação covalente)

f. Li₂O- ionic bonding (ligação iônica)

g. CO₂ - double covalent bonding (ligação covalente dupla)

h. MgCl₂- ionic bonding(ligação iônica)


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You're taking your first dive in ALVIN (Fig 10.13) to witness a hot spot on the ocean floor. As you descend and arrive on site, what are your first impressions?
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A roller coaster cart of mass m = 223 kg starts stationary at point A, where h1 = 26.8 m and a while later is at B, were h2 = 14.7 m. The acceleration of gravity is 9.8 m/s 2 . What is the speed of the cart at B, ignoring the effect of friction?

Answers

Answer:

vB = 15.4 m/s

Explanation:

Principle of conservation of energy:

Because there is no friction the mechanical energy is conserve

ΔE = 0

ΔE : mechanical energy change (J)

K : Kinetic energy (J)

U: Potential energy (J)

K = (1/2)mv²

U = m*g*h

Where :

m: mass (kg)

v : speed (m/s)

h : hight (m)

Ef - Ei = 0

(K+U)final - (K+U)initial =0

(K+U)final = (K+U)initial

((1/2)mv²+m*g*h)final = ((1/2)mv²+m*g*h)initial , We divided by m both sides of the equation:

((1/2)vB² + g*hB = (1/2 )vA²+ g*hA

(1/2) (vB)² + (9.8)*(14.7) =  0 + (9.8)(26.8 )

(1/2) (vB)² = (9.8)(26.8 ) - (9.8)*(14.7)

(vB)² = (2)(9.8)(26.8 - 14.7)

(vB)² = 237.16

v_(B) = √(237.16)

vB = 15.4 m/s : speed of the cart at B

Answer:

the guy above me is correct

Explanation:

The photos of an electromagnetic wave us 1. 5 × 10^-24 j of energy , what kind of electromagnetic waves are they ?

Answers

The electromagnetic waves with an energy of 1.5 * 10^(-24)  J are likely X-rays.

The energy of an electromagnetic wave is related to its frequency and wavelength by the equation:

E = hf = hc/λ

where:

E = energy of the electromagnetic wave

h = Planck's constant (6.626 * 10^(-34)  J s)

f = frequency of the electromagnetic wave

c = speed of light (3.00 * 10^8 m/s)

λ = wavelength of the electromagnetic wave

Solving for λ:

λ = hc/E = (6.626 * 10^(-34)  J s)(3.00 * 10^8 m/s)/(1.5 * 10^(-24)  J)

λ ≈ 4.40 * 10^-8 m

This corresponds to a wavelength of about 44 nanometers, which falls in the range of X-rays. Therefore, the electromagnetic waves with an energy of 1.5 * 10^(-24)  J are likely X-rays.

for such more question on electromagnetic Wave

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True or false one of the benefits of using an exercise ball is generally involves the core muscles?

Answers

the answer is true improve core stability
This is true in many cases, but not all. There are exercises in which you simply raise and lower an exercise ball over your head (kind of like weight lifting), but whenever the ball is in front of you and you reach out at all with your arms, that is a core workout. 

Four parallel-plate capacitors are constructed using square plates, and each has a dielectric inserted between the plates.?Rank the capacitance of each capacitor in order from highest to lowest.

A = side length (L/2) ; distance between plates (d) ; dielectric current (k)

B = side length (L) ; distance between plates (d/2) ; dielectric current (4k)

C = side length (2L) ; distance between plates (d) ; dielectric current (2k)

D = side length (L) ; distance between plates (2d) ; dielectric current (2k)

Answers

Final answer:

The capacitance of the four capacitors, ranked from highest to lowest, is B = C (they both have equal capacitance), followed by D, and then A.

Explanation:

The capacitance of a parallel-plate capacitor is given by C = εA/d, where ε is the permittivity of the dielectric material (which is equal to the product of the vacuum permittivity and the relative permittivity or dielectric constant k), A is the area of one of the plates, and d is the separation between the plates.

Applying this formula to the four capacitors and simplifying:

  1. Capacitor A: Cap = k(0.5L)^2/d = 0.25kL^2/d
  2. Capacitor B: Cap = 4k(L)^2/(0.5d) = 8kL^2/d
  3. Capacitor C: Cap = 2k(2L)^2/d = 8kL^2/d
  4. Capacitor D: Cap = 2k(L)^2/(2d) = kL^2/d

When ranked from highest to lowest capacitance, the order will be B = C > D > A.

Learn more about Capacitance here:

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NEED ASAP PLEASE !!! Suppose that a block is pulled 16 meters across a floor. What amount of work is done if the force used to drag the block is 22 N?

A. 200 J
B. 330 J
C. 352 J
D. 220 J

Answers

Answer: Option (C) is the correct answer.

Explanation:

Work is defined as the energy required when force is applied in a certain direction.

The expression for work, force and distance is as follows.

                        W = F × d

where,      W = work

                 F = force

                 d = distance

It is given that force applied to drag the box is 22 N and distance is 16 meters. Therefore, calculate work done as follows.

                        W = F × d

                            = 22 N × 16 meters

                            = 352 Nm               (1 Newton meter = 1 joule)

or,                   W = 352 J

Thus, we can conclude that amount of work done is 352 J.

work = force x distance
22N x 16m = 352 J

Phileas Fogg, the character who went around the world in 80 days, was very fussy about his bathwater temperature. It had to be exactly 38.0o C. You are his butler, and one morning while checking his bath temperature, you notice that it’s 42.0oC. You plan to cool the 100.0 kg of water to the desired temperature by adding an aluminum-duckie originally at freezer temperature (-24.0oC). Of what mass should the Al-duckie be? [Specific heat of Al = 0.900 J/(goC); density of water =1 .00 g/ml]. Assume that no heat is lost to the air

Answers

Answer:

The mass of the Al-duckie should be 30 kg.

Explanation:

We will use the first law of thermodynamics:

ΔU = m·Cv·ΔT

Since the specific heat of water is 4.185 J(gºC), the change in the water's internal energy would be:

ΔU = 100 kg · 4.185 J(gºC) · (42ºC - 38ºC) = 1674 KJ

Given that no heat is lost, all the internal energy that the water loses while cooling down will transfer to the duckie.  So, if the duckie has ΔU = 1674 KJ and its final temperature is the desired 38 ºC, we can calculate its mass using the first law again:

m=\frac{\Delta{U}}{Cv{\Delta{T}}}=(1674)/(0.9*[38-(-24)])=30Kg