MATHEMATICS HIGH SCHOOL

HELPPPPPPPP4 Renting video games from Store S costs $2.50 per game plus a monthly fee of

$5.00. Renting video games from Store T costs $5.00 per game with no monthly
fee. The monthly cost to rent video games depends on the number of video
games, v, rented. Which equation represents the situation when the monthly cost
at Store S is equal to the monthly cost at Store T?
F 2.5v + 5 = 5v
G 2.5 + 5v = 5v
H 7.5v = 5v
J 7.5v = 10v

Answers

Answer 1
Answer:

Answer:

it is c

Step-by-step explanation:

because I said it is

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Evaluate inverse functions PLEASE HELPPP!!!

Answers

use photomath its are helpful

Is x+1 a factor of the function f(x)=2x⁵-4x⁴+9x³-x+13?Show work supporting your answer.

Answers

Answer:

(x+1) will not be factor of given polynomial

Step-by-step explanation:

We have given polynomial f(x)=2x^5-4x^4+9x^3-x+13

We have to find that  is (x+1) factor of the given polynomial

If (x+1) will be the factor of the polynomial then x= -1 will be the root of the polynomial

And if we put x =-1 in the pronominal then then its value will be zero

f(-1)=2(-1)^5-4(-1)^4+9(-1)^3-(-1)+13=-2-4-9+1+13=-1

So (x+1) will not be factor of given polynomial

Please help me limited time

Answers

Answer:

its 1

Step-by-step explanation:

Answer:

its number one

Step-by-step explanation:

thank you and I'm sure

Compare using <, >, or =.
5 3/4___6 1/4

Answers

the answer would < because 6 1/4 is larger than 5 3/4. Hope that helps!

I REALLY NEED HELP WITH THIS I HAVE NO CLUE WHAT IM DOING PLEASE HELP!!!!!!!!!!!!! F(x)=9x^3+2x^2-5x+4 and g(x)=5x^3-7x+4. what is f(x)-g(x)? show all of your steps and write your final answer in factored form

Answers

f(x)=9x³+2x²-5x+4
g(x)=5x³-7x+4

f(x)-g(x)=(9x³+2x²-5x+4)-(5x³-7x+4)=
=9x³+2x²-5x+4-5x³+7x-4=
=(9x³-5x³)+2x²+(-5x+7x)-4=
=4x³+2x²+2x-4

Answer; f(x)-g(x)=4x³+2x²+2x-4

Express 15% as a fraction

Answers

15/100=15% 

hope this helps

15/100

this is the easiest way to learn how to turn numbers like these in fractions is if you put a10 or 100 behind them

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