Write the equation in slope-intercept form. 4x+3y=18Question 7 options:

y=43x+6

y=−34x+184

y=−43x+6

y=4x+6

Answer:

No, the manager is not correct based on the 95% confidence interval.

Step-by-step explanation:

We are given that the average daily revenue over the past five-week period has been $1,080 with a standard deviation of $260, i.e.; X bar = $1080 and s = $260 and sample size, n = 35 .

The Pivotal quantity for 95% confidence interval is given by;

                ~

where, X bar = sample mean = $1080

                s  = sample standard deviation = $260

                 n = sample size = 35 {five-week}

So, 95% confidence interval for average daily revenue, is given by;

P(-2.032 < < 2.032) = 0.95

P(-2.032 < < 2.032) = 0.95

P(-2.032 * < < 2.032 * ) = 0.95

P(X bar - 2.032 * < < X bar + 2.032 * ) = 0.95

95% confidence interval for = [ X bar - 2.032 * , X bar + 2.032 * ]

                                            = [ 1080 - 2.032 * , 1080 + 2.032 * ]

                                             = [ 990.70 , 1169.30 ]

No, the manager is not correct based on the fact that the coffee and pastry strategy would lead to an average daily revenue of $1,200 because the calculate 95% confidence interval does not include value of $1200.

Therefore, the store manager believe is not correct.

Final answer:

The 95% confidence interval for the store's average daily revenue is calculated to be approximately ($993.97, $1166.03). Since $1200 is outside this interval, the manager's belief that the coffee and pastry strategy will lead to an average daily revenue of $1200 is not backed by this confidence level.

Explanation:

In the field of statistics, a confidence interval (CI) is a type of interval estimate that is used to indicate the reliability of an estimate. The method for calculating a 95% confidence interval for the average daily revenue involves the sample mean, the standard deviation, and the z-score associated with a 95% confidence level, which is approximately 1.96. Let's use the provided data to calculate:

• Calculate the standard error by dividing the standard deviation by the square root of the sample size. Here, the standard deviation is $260, and the sample size is 5 weeks * 7 days/week = 35 days. So, the standard error is $260 / sqrt(35) = $43.89.
• Multiply the standard error by the z-score to get the margin of error. So, $43.89 * 1.96 = $86.03.
• Calculate the lower and upper bounds of the 95% confidence interval by subtracting and adding the margin of error from/to the sample mean. So, ($1080 - $86.03, $1080 + $86.03) = ($993.97, $1166.03).

The range of this 95% confidence interval is from $993.97 to $1166.03. This means we are 95% confident that the true average daily revenue lies within this interval. Since $1200 lies outside this interval, the manager's belief is not supported by this confidence interval.

Learn more about Confidence Interval here:

brainly.com/question/34700241

#SPJ3

Answer:

Parallel: y = 3x +b, where b ≠ 4

Perpendicular: y = -1/3x + b

Step-by-step explanation:

Parallel Lines have the same slope but different y-intercepts.

Perpendicular Lines have a negative reciprocal in slope.

Answer:

The number of times organism B's population is larger than organism A's population after 8 days is 32 times

Step-by-step explanation:

The population of organism A doubles every day, geometrically as follows

a, a·r, a·r²

Where;

r = 2

The population after 5 days, is therefore;

Pₐ₅ = = 32·a

The virus cuts the population in half for three days as follows;

The first of ta·2⁵ he three days = 32/2 = 16·a

The second of the three days = 16/2 = 8·a

After the third day, Pₐ = 8/2 = 8·a

The population growth of organism B is the same as the initial growth of organism A, therefore, the population, P₈ of organism B after 8 days is given as follows;

P₈ =  a·2⁸ = 256·a

Therefore, the number of times organism B's population is larger than organism A's population after 8 days is P₈/Pₐ = 256·a/8·a = 32 times

Which gives, the number of times organism B's population is larger than organism A's population after 8 days is 32 times.

Final answer:

Organism A's population at the end of 5 days is 2^5. After 5 days, a virus cuts it in half for 3 days. Organism B's population at the end of 8 days is 2^8. To find the difference, subtract organism A's population from organism B's population.

Explanation:

Organism A's population doubles every day for 5 days, so the population at the end of 5 days is 25. After 5 days, a virus cuts the population in half for 3 days, so we need to find (25) * (2-1)3. Using the rule of exponents, we can rewrite this expression as (25+(-1*3)), which simplifies to 2-4.

Organism B's population grows at the same rate but is not infected with the virus. After 8 days, the population is 28.

To find out how much larger organism B's population is than organism A's population, we need to subtract the population of organism A from organism B. So, 28 - 2-4 is the answer.

Learn more about Population growth and virus impact here:

brainly.com/question/32372080

#SPJ3

Answer:

-3/2, -2, 0, 2.1, 7/3

Step-by-step explanation:

Please correct me if I am wrong. Thank you.

Answer:

Chris's total earning will be: $306.25

Step-by-step explanation:

Given:

Total number of dogs = d = 5

Number of weeks = w = 7

Cost for walking per dog = c = $8.75

First of all, we will calculate his per week cost of walking 5 dogs

Per week cost of walking 5 dogs = d*c = 8.75*5 = $43.75

Then for the cost of 7 weeks, the amount of one week will be multiplied by 7

Total earning will be:

Hence,

Chris's total earning will be: $306.25

Answer:

he should be making $306.25

Step-by-step explanation:

what i did was multiply his $8.75 a dog by 5 then multiply it by the 7 weeks