Other words for saying that a wave is "transmitted" through a medium are transmission, propagation, spread.
"Wave is a phenomenon or disturbance in which energy is transferred from one point to another without any direct contact between them." For example: Heat, light and sound is considered as a wave.
Know more about wave here
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Answer:
Other words for saying that a wave is transmitted through a medium would be a wave transfers from one medium into another.
Explanation:
Given: Takeoff Speed (u) = 28 m/s
Final velocity (v) = 0.0 m/s
Acceleration (a) = 1.9 m/s²
To calculate: The minimum length of runway (s) =?
Solution: Apply 3rd kinematic equation of motion
v² = u² - 2as
Or, s = ( u² - v²) / 2 a
Or, s = ( 28² - 0²) / 2 × 1.9 m
Or, s = 206.3 m
Hence, the required minimum length of the runway will be 206.3 m
To determine the minimum length of the runway a Cessna 150 airplane would need to take off, you can use a kinematic equation. Plugging in a final velocity of 28 m/s, initial velocity of 0 m/s (since the plane starts from rest), and acceleration of 1.9 m/s/s gives an answer of approximately 207.11 meters.
The subject of your question is related to physics, specifically, kinematics, which studies the motion of objects. In your case, a Cessna 150 airplane needs to accelerate from rest to a speed of 28 m/s for takeoff, with an average acceleration of 1.9 m/s/s, and you're trying to find out the minimum length of the runway required. For this, we can use a kinematic equation.
The equation we can use is the following: v^2 = u^2 + 2as, where v is the final velocity (28 m/s), u is the initial velocity (0 m/s since the plane starts from rest), a is the acceleration (1.9 m/s/s), and s is the distance we want to find out.
When you plug in the known values into the equation, you will get: (28)^2 = (0)^2 + 2 * 1.9 * s. After rearranging the equation, you will have s = [(28)^2 - (0)^2] / 2*1.9 = 207.11 m. Therefore, the minimum length of the runway required for the Cessna 150 airplane to take off is approximately 207.11 meters, assuming constant acceleration and no other factors interfering.
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B. Cobweb
C. Mustardseed
D. Puck
In both scenarios, the work done on the heavy block is the same, as it is determined by the change in the vertical height. However, pulling the block up the inclined plane may require less force because the work is distributed over a larger distance.
The subject of this question is based on the concept of work and energy in physics. When you pull the heavy block straight upwards (scenario a), the work done is equal to the force times the distance, or Work = mg*h, where m is the mass of the block, g is the acceleration due to gravity, and h is the height it needs to rise. For pulling the block up the inclined plane (scenario b), the work done still equals mg*h as the vertical distance it rises is the same.
This is because, according to the principle of work and energy, the work done on an object is equal to the change in its kinetic energy. Since the speed of the block remains constant in both scenarios, the kinetic energy does not change, meaning the work done on the block is the same in both scenarios.
However, pulling the block up the inclined plane may require less force because of the larger distance over which the work is done. But the overall work is the same in both cases.
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Answer:
I’m so sorry I tried solving it but I don’t understand it can you explain the question a little bit more ty
Explanation:
a. the volume of the container that the gas is in
b. the percentage of the gas
c. the percentage of the other gases that comprise the atmosphere
d. the total pressure in the atmosphere
Answer:
C.)
Explanation:
i said c because. idk i guessed sry