A 1200 kg car starts from rest and travels 100m in a time of 10 seconds . A) what is the acceleration of the car? B) what force must have acted on the car during this time? C) what is the velocity of the car after 10 seconds? D) what work was done on the car? E) what minimum power did the engine produce?

Answers

Answer 1

Answer: Given:
Mass (m) = 1200 kg
Distance (s) = 100 m
Time (t) = 10 seconds
Now,
$velocity (v) = (distance)/(time)$

= $(100~ m)/(10~seconds)$

= 10 m/s
Note that this one is the final velocity.
We also know that,
initial velocity (u) = 0 m/s .......because the car starts from rest.
Now,
$acceleration (a)= (change~in~velocity)/(time)$

= $(v-u)/(t)$

= $(10-0)/(10)$

= 1 m/s²
Now,
Force (F) = mass (m) * acceleration (a)
= 1200 kg * 1 m/s²
= 1200 kg.m/s²
= 1200 N
Now,
Work Done (W) = Force (F) * displacement (s) ....note that displacement is same as distance.
= 1200 N * 100 m
= 120000 N.m
= 120000 J
Now,
Power (P) = $(Work~done(W))/(time(t))$

= $(120000~J)/(10s)$

= 12000 J/s
= 12000 watt
SO,
A) The acceleration of the car is 1 m/s².
B) 1200 Newton (N) force must have acted on the car.
C) The velocity of the car after 10 seconds is 10 m/s.
D) 120000 Joule (J) work was done on the car.
E) The engine produced a minimum power of 12000 watt.

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Answers

The answer is false! Hope that helps! :)

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Answers

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A car passes the Eiffel tower driving at a constant rate of 60 km per hour. A second car, traveling at a constant rate of 75 km per hour, passes the Eiffel tower a while later and then follows the first car. It catches the first car after traveling a distance of 75 km past the Eiffel tower. How many minutes after the first car passed the Eiffel tower did the second car pass the Eiffel tower

Answers

Answer:

300 minutes.

Explanation:

Given,

Speed of car 1 = 60 Km/h

Speed of car 2 = 75 Km/h

distance travel by car 2 to catch car 1 = 75 Km

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A traveler first drives 18.6 km east, then 30.3 km southeast, and finally 10.7 km south. Find the traveler's total displacement ?

Answers

If a traveler first drives 18.6 km east, then 30.3 km southeast, and finally 10.7 km south then the traveler's total displacement would be 51.30 kilometers.

What is displacement?

An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard. Displacement describes this shift in location.

As given in the problem If a traveler first drives 18.6 km east, then 30.3 km southeast, and finally 10.7 km south then we have to find the traveler's total displacement,

the total displacement in the east direction = 18.6 + 30.3Cos45°

the total displacement in the east direction = 40 km

the total displacement in the south direction = 10.7 + 30.3Cos45°

the total displacement in the south direction = 32.12 km

The net resultant displacement = √(40² + 32.12²)

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Thus, the traveler's total displacement comes out to be 51.30 kilometers.

Learn more about displacement here, refer to the link;

brainly.com/question/10919017

#SPJ2

East: 18.6+30.3/(sqrt2)
South: 19.7+30.3/(sqrt2)
Total displacement: sqrt(east^2+south^2) is 57.3 km

The conductive tissues of the upper leg can be modeled as a 40- cm-long, 12-cm-diameter cylinder of muscle and fat. The resistivities of muscle and fat are 13 Ω m and 25 Ω m, respectively. One person’s upper leg is 82% muscle, 18% fat. What current is measured if a 1.5 V potential difference is applied between the person’s hip and knee?

Answers

Answer:

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Explanation:

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