Which two equations are equivalent

Answers

Answer 1

Answer:

Answer: a and b

Step-by-step explanation:

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TIME REMAINING54:32
Tom would like to take out a secured loan to help pay for a vacation this summer. He has offered his car as collateral.
His car is worth $3,500. His bank can offer loans for 80% of collateral value. The vacation he has planned will cost
$4,750. Approximately how much additional collateral will Tom need to offer in order to borrow enough to go on his
vacation as planned?
$1,000.00
b. $1,362.50
c. $2,437.50
d. $2,800.00
a.
Please select the best answer from the choices provided
A
B.
ОООО
D

Answers

Tom will need to offer additional collateral of C. $2,437.50 to borrow enough for his planned vacation.

What is collateral?

Collateral refers to a valued property or financial security offered by the borrower to the lender to guarantee repayment of a loan.

Lenders sell collaterals when the borrowers fail to comply with their loan terms.

How is the additional collateral determined?

Car's value = $3,500

Collateral value in percentage = 80%

Car's collateral value = $2,800 ($3,500 x 80%)

Planned cost of vacation = $4,750

Additional cost to meet vacation cost = $1,950 ($4,750 - $2,800)

Additional collateral value to meet target = $2,437.50 ($1,950/80%)

Total collateral that Tom needs to offer = $5,937.50 ($3,500 + $2,437.50)

80% of $5,937.50 = $4,750

Another way is to work with the planned cost and the collateral percentage offered by Tom's bank:

Planned cost of vacation = $4,750

Collateral value in percentage = 80%

Total collateral to be offered by Tom = $5,937.50 ($4,750/80%)

Car's collateral value = $3,500

Additional collateral value = $2,437.50 ($5,937.50 - $3,500)

Thus, Tom needs additional collateral of C. $2,437.50.

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The universal set in this diagram is the set of integers from 1 to 15. Place the integers in the correct place in the Venn Diagram.please help, i’ve been stuck on this assignment for almost an hour now and i can’t figure it out..

20 points and branliest!!!

Answers

The integers placed in the correct place in the Venn Diagram is attached

Placing the integers in the correct place in the Venn Diagram.

From the question, we have the following parameters that can be used in our computation:

Set = 1 to 15

From this set of 15 integers, we have the following subsets of numbers

Factors of 15: 1, 3 and 5

Odd Integers: 1, 3, 5, 7, 9, 11, 13 and 15

Multiples of 3: 3, 6, 9, 12 and 15

Also, we have the following intersection sets

Factors of 15 and Multiples of 3: 3

Factors of 15 and Odd Integers: 1, 3, 5

Multiples of 3 and Odd Integers: 3, 9, and 15

All: 3 and 15

None: 2, 4, 8, 10 and 14

The complete Venn diagram is attached

Answers

a. The probability that at least 13 of the next 15 motherboards pass inspection is 0.604.

b. On average, 1.1765 motherboards should be inspected until a motherboard that passes inspection is found.

The formula for the probability of getting exactly k successes in n trials with a success probability of p is:

$P(X = k) = (^nC_k) * p^k * (1 - p)^((n - k))$

Where "n choose k" represents the binomial coefficient, which is calculated as n! / (k! * (n - k)!), where "!" denotes factorial.

In this case:

n = 15 (number of trials)

k = 13, 14, 15 (number of successes)

p = 0.85 (probability of success)

First, let's calculate the probability that exactly 13, 14, and 15 motherboards pass inspection.

For k = 13:

$P(X = 13) = (^(15) C_ {13}) * 0.85^(13) * (1 - 0.85)^((15 - 13))$

= 0.28564

For k = 14:

$P(X = 14) = (^(15) C_(14)) * 0.85^(14) * (1 - 0.85)^((15 - 14))$

= 0.23123

For k = 15:

$P(X = 15) = (^(15) C_(15)) * 0.85^(15) * (1 - 0.85)^((15 - 15))$

= 0.08735

Now, sum these probabilities to get the final answer:

P(at least 13) = P(X = 13) + P(X = 14) + P(X = 15)

= 0.28564 + 0.23123 + 0.08735

= 0.60422

= 0.604

(b)

The average number of trials needed until a motherboard that passes inspection is found can be calculated using the concept of the expected value of a geometric distribution:

Expected value (E) = 1 / p

Where p is the probability of success.

In this case, p = 0.85.

E = 1 / 0.85

= 1.1765

Thus, on average, 1.1765 motherboards should be inspected until a motherboard that passes inspection is found.

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Final answer:

To find the probability that at least 13 of the next 15 motherboards pass the inspection, use the binomial formula for each scenario (13, 14, and 15 passing) and sum the results. To find on average how many motherboards need to be inspected for one to pass inspection, just take the reciprocal of the probability of success (1/0.85).

Explanation:

This question falls under the domain of probability and statistics. Let's tackle each part separately:

(a) When we talk about at least 13 out of 15 motherboards passing, we have to consider the situations where exactly 13, 14, or all 15 pass. For each case, you would use the binomial formula P(X=k) = C(n, k) * (p^k) * ((1-p)^(n-k)). In this formula, n is the number of trials (which is 15), k is the number of successes we are interested in, p is the probability of a success (which is 0.85), C(n, k) is a combination that represents the different ways k successes can happen in n trials. Calculate this for k = 13, 14, and 15 and sum the results to get the probability for at least 13 to pass.

(b) To find on average how many motherboards should be inspected until one passes is straightforward - it is simply the reciprocal of the probability of success which is 1/0.85.

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Hello, please I bed urgent help with this math problem please

Answers

Answer:

option C

Step-by-step explanation:

$4c^2 + 7c - 5 = 0 , \ where \ a = 4 , \ b = 7 , \ x = - 5$

$c = (- b \pm √(b^2 - 4ax ))/(2a) \n\nc = (- 7 \pm √(49 - ( 4 * 4 * - 5 )))/(2 * 4) \n\nc = (- 7 \pm √(49 + 80))/(8) \n\nc = (- 7 \pm √(49 + 80))/(8) \n\nc = (- 7 \pm √(129))/(8) \n\n$

Answer:

Option C

Step-by-step explanation:

Quadratic formula:

$4c^(2) +7c-5=0$

$a=4\nb=7\nx=-5$

$c=\frac{-b\frac{+}{} √(b^2-4ax)}{2a}$

$c=\frac{-7\frac{+}{}49-(4*4*-5) }{2*4}$

$c=\frac{-7\frac{+}{}√(129) }{8}$

hope this helps....

Robin can clean 727272 rooms in 666 days. how many rooms do she clean in 9 days

Answers

Answer:

Robin can clean 9828 rooms in 9 days

Step-by-step explanation:

Since Robin can clean 727272 rooms in 666 days, we can find how many rooms she can clean in 1 day by dividing 727272 by 666

number of rooms cleaned by Robin in 1 day = 727272 rooms/666 days = 1092 rooms/day

We can then find how many rooms she can clean in 9 days by multiplying 1092 by 9

1092 rooms/day * 9 days = 9829 rooms

What is the missing number in the following sequence?78, 66, ____, 42, 30

a. 51
b. 53
c. 54
d. 55

Answers

Final answer:

The missing number in the sequence is 54.

Explanation:

The missing number in the sequence is 54.

To identify the missing number, we need to observe the pattern in the sequence. The sequence decreases by 12 each time. Starting from 78, we subtract 12 to get 66, then subtract 12 again to get 54, and so on. Therefore, the missing number is 54.

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