Answer:
Slope of a line passing through (,
) and (
) is given by:
Now,
Slope of line L, (m) = = 0.5
Slope of line M, (n) = =
If the lines L and M are parallel to each other,
m = n
or, 0.5 =
or, 0.5 (W - 1) = -2
or, W - 1 = -4
or, W = -3
Therefore the required value of W is -3.
select the explicit function which defines the sequence.
A.) f(n) = 1/3 • 2^(n - 1)
B.) f(n) = 2 • (1/3)^(n - 1)
C.) f(n) = 1/3 • 3^(n - 1)
D.) f(n) = 3 • (1/3)^(n - 1)
Answer:
D
Step-by-step explanation:
Answer:
She would use 136 yards in 4 skirts, 238 yards in 7 skirts, and 306 yards in 9 skirts. Hope this helps
Step-by-step explanation:
Answer:
18 = number of players
Step-by-step explanation:
Giving the following information:
Members of a softball team raised $2039.50 to go to a tournament. They rented a bus for $1157.50 and budgeted $49 per player for meals.
To calculate the total number of players they can bring, we need to use the following formula:
Total amount of money= fixed cost + unitary variable cost*number of players
2,039.5= 1,157.5 + 49*number of players
882/49= number of players
18 = number of players
The team can bring a maximum of 18 players to the tournament given the amount they raised and the budgeted expenses.
Let's use "x" to represent the number of players the team can bring to the tournament.
The total amount raised by the team is $2039.50,
and they rented a bus for $1157.50. Each player's meal will cost $49.
The total amount spent on the bus and meals for x players can be represented as follows:
Total Expenses = Bus Cost + (Number of Players) * (Cost per Player's Meal)
= $1157.50 + x * $49
Since the team's total expenses should not exceed the total amount raised,
$2039.50 ≥ $1157.50 + x * $49
$2039.50 - $1157.50 ≥ x * $49
$882 ≥ x * $49
Now, divide both sides by $49 to solve for x:
x ≤ $882 / $49
x ≤ 18
So, the team can bring a maximum of 18 players.
Learn more about Inequality here:
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cross multiplication.
Answer:
B.
Step-by-step explanation:
In the attached file
Answer:
B
Step-by-step explanation:
I put the answer in an atachement