MATHEMATICS HIGH SCHOOL

Help plssss it’s timed ty

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Answer 1

Answer:

Answer:

A is the correct answer m8

line AB is a chord

Step-by-step explanation:

Any line that segments a circle and joins two points at the circumference of a circle is called a chord.

line AB is a chord

While

line EC is a diameter

line DF is a radius

Answer:

Correct Answer should be AB

Step-by-step explanation:

I toke the quiz so I know its correct

a 5ft ladder is leaning against a 4 ft wall. how far must the bottom of the ladder be from the wall so that the top of the ladder rests on the top of the wall?

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The ladder leaning against the wall forms a right angled triangle with the gound and the wall. So we can use the formula:

a² + b² = c²

The ladder is the hypotenuse c²

The vertical leg is b²

The base or horizontal leg is a²

We need to find the length of the base a², so:

a² = c² - b²

a² = 5² - 4²

a² = 25 - 16

a² = 9

a = √9

a = 3

Therefore the bottom of the ladder must be 3 feet from the wall.

What is the difference of the two polynomials?(7y^2 + 6xy) – (–2xy + 3)

A.) 7y^2 + 4xy – 3

B.) 7y^2 + 8xy – 3

C.) 7y^2 + 4xy + 3

D.) 7y^2 + 8xy + 3

Answers

Answer:

B) 7y² + 8xy - 3 .

Step-by-step explanation:

Given : (7y² + 6xy) – (–2xy + 3).

To find : What is the difference of the two polynomials.

Solution : We have given

(7y² + 6xy) – (–2xy + 3).

Removing the pantheists

(7y² + 6xy) + 2xy - 3).

Combine like terms

7y² + 8xy - 3 .

Therefore, B) 7y² + 8xy - 3 .

the answer to that question is B.

Find the exact value of cos(135 degree + 30 degree)

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$cos(x+y)=cosxcosy-sinxsiny\nsin(x+y)=sinxcosy+sinycosx\n-------------------------------\ncos(135^o+30^o)=cos135^ocos30^o-sin135^osin30^o=(*)\n----------------------------\ncos135^o=cos(90^o+45^o)=cos90^ocos45^o-sin90^osin45^o\n=0\cdot(\sqrt2)/(2)-1\cdot(\sqrt2)/(2)=-(\sqrt2)/(2)\n\nsin135^o=sin(90^o+45^o)=sin90^ocos45^o+sin45^ocos90^o\n=1\cdot(\sqrt2)/(2)+(\sqrt2)/(2)\cdot0=(\sqrt2)/(2)\n-------------------------------$

$(*)=-(\sqrt2)/(2)\cdot(\sqrt3)/(2)-(\sqrt2)/(2)\cdot(1)/(2)=-(√(6))/(4)-(\sqrt2)/(4)=-(\sqrt6+\sqrt2)/(4)$

Solve ry + s = tx - m for y. Explain each step in your solution?A. Would there be any limitations for the value of each variable? If so, explain the limitation?

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Let's solve for mry+s=tx-mstep 1: Flip the equationstx-m=ry+sstep 2: Add -tx to both sidestx-m+(-tx)=ry+s+(-tx)-m=ry-tx+sstep 3 :Divide both sides by -1-m-1=ry-tx+s-1m=-ry+tx-sI hoped i help :)

Pls pls help me bro i’m abt to fail

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10 hours babysitting and 3 tutoring

Help plssss it’s timed ty

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line AB is a chord

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