Why does 0.50 m equal to 50 cm???

Answers

Answer 1
Answer: because to convert from m to cm you have to times it by 100, so 0.50 m times 100 is 50 cm

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Find the values of x and y if

Solve 3y + 20 = 3 +2y

Answers


3y + 20 = 3 + 2y

3y- 2y = 3-20

y = -17

3y+ 20= 3+ 2y
⇒ 3y -2y= 3 -20 (inverse operation)
⇒ y= -17

Final answer: y= -17.

Use the rules of multiplication by powers of 10 to calculate 20 times 100.

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its 2000 becasue 200* 10 eqoals 2000
The answer is 2000 because 20 times 100 it equals 2000

How far away would you need to place the ladder​

Answers

Answer:

Step-by-step explanation:

far away

Answer:3 inches

Step-by-step explanation:

Identify the center and radius of a circle with equation (x+4)^2+(y-2)^2=36

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In the equation of a circle in the form (x-h)^2 + (y-k)^2 = r^2, (h,k) is the center and r is the radius.

So, the center of the circle is at (-4,2) with radius 6 units.

A taut string of length 10 inches is plucked at the center. The vibration travels along the string at a constant rate of c inches per millisecond in both directions. If x represents the position on the string from the left-most end, so that 0≤x≤10, which of the following equations can be used to find the location x of the vibration after 0.3 milliseconds? A. | x -5 | =0. 3 B. ∣cx−5∣=0.3 C. | x -0.3 | = 5 D. | x - 10 | =0.3c

Answers

Answer:

The correct option is

A.  \ (1)/(c) * \left | x - 5 \right | = 0.3

Step-by-step explanation:

The parameters given are;

The length of the string = 10 inches

The speed or rate of travel of the wave = c inches per millisecond

The position on the string from the left-most end = x

The time duration of motion of the vibration to reach x= 0.3 milliseconds

The distance covered = Speed × Time = c×0.3

Given that the string is plucked at the middle, with the vibration travelling in both directions, the point after 0.3 millisecond is x where we have;

The location on the string where it is plucked = center of the string = 10/2 = 5 inches

Distance from point of the string being plucked (the center of the string) to the left-most end = 5 inches

Therefore, on the left side of the center of the string we have;

The distance from the location of the vibration x (measured from the left most end) to the center of the string = 5 - x = -(x -5)

On the right side of the center, the distance from x is -(5 - x) = x - 5

Therefore, the the equation that can be used to find the location of the vibration after 0.3 milliseconds is (1)/(c) * \left | x - 5 \right | = 0.3 or \left | x - 5 \right | = 0.3 * c which gives the correct option as A

Which inverse operation would be used to verify the following equation? 54 ÷ 9 = 6        A. 9 − 6 = 3   B. 54 ÷ 6 = 9   C. 9 × 6 = 54   D. 9 + 6 = 15

Answers

  C. 9 × 6 = 54 is the answer.

9 X 6 = 54. They are opposite operations