If a 4000 watt oven is on for 5 hours, then how many kilowatt-hours (kw-hrs) of energy are used?
Solution: We are given that the oven is 4000 watt and it is on for 5 hours.
We have to find the how many kilowatt-hours (Kw-hrs) of energy are used by the oven.
We first need to convert watts into kilowatt's. We know that:
Therefore, 4000 Watts
Now, we can find how many kilowatt-hours (Kw-hrs) of energy are used by the oven.
Energy used by the oven Kw-hrs
Therefore, 20 kilowatt-hours (kw-hrs) of energy are used by the oven.
Answer:
3 multiplied by a variable d and add seven to it
Step-by-step explanation:
3 multiplied by a variable d and add seven to it.
Answer:
11. True
12. false
13. True
14. False
15. true
16. True
sry if number 15 & 16 are wrong,
17. Line AE, Line FE, Line HE
18. Plane ABCD
19. Plane ABCD , Plane CDHG
20. Plane CDHG, Plane ABCD, Plane ADHE
hope this helps :)
For A to B, or segment AB, we have the points (1,1) and (4,3). (x1, y1) = (1,1) and (x2, y2) = (4,3);
x = 1 + t(4 - 1)
y = 1 + t(3 - 1)
A to B => (x = 1 + 3t, y = 1 + 2t)
We can apply a similar process for BC and AC. For BC we have (x1, y1) = (4,3) and (x2,y2) = (1,7);
x = 4 + t(1 - 4)
y = 3 + t(7 - 3)
B to C => (x = 4 - 3t, y = 3 + 4t)
(x1, y1) = (1, 1) and (x2, y2) = (1, 7);
x = 1 + t(1 - 1)
y = 1 + t(7 - 1)
A to C => (x = 1, y = 1 + 6t)
Here is your graph of the triangle. Desmos is a really great tool to use;
Answer:
8
Step-by-step explanation:
x² − x = 56
x² − x − 56 = 0
(x − 8) (x + 7) = 0
x = -7 or 8
x is positive, so x = 8.