Find the slope that passes through (-1, -3) and (-2, 2).A
-5
С
-2
B
-1/5
D
1/3
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Answer:
A.-5
Step-by-step explanation:
I have used an online calculator to check my answer against so this answer is 100% correct. I used "Slope Calculator" by Omni.
PLEASAE MARK BRAINLIEST
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URGENT!!! What is the coefficient of the x4-term in the binomial expansion of (x + 3)12?
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it would cost 6.4
sorry I do not know how to put up that money sign
Multiply diagonally:
Divide by 100 on both sides:
Therefore, 80cm of kitchen flooring would cost £6.40.
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You could have a Quadratic with 2 distinct solution meaning you have 2 different X intercepts
2 roots means the discriminan is positive in other words
D>0
When the discriminan is 0, D=0 we have exactly one x-intercept.
Discriminan D=0
and finally, if the discriminan were negative
D=0
then there is no solution or root at all.
(;-; my hand hurts)
Step-by-step explanation:
he/ she is right that's the answer
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Answer:
7 squared is 49 4 squared is 16.. So it's 49 Pi minus 16 pi. And that's going to be 33 pi.
So the answer is 33 pi.
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-30r^2s^2t+18rst^2
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Answer:
the total cost of paint and tiles needed to decorate the community hall is £105 + £900 = £1005.
Step-by-step explanation:
Area of the walls:
- The community hall is shaped like a cuboid, so the walls are the four rectangular sides.
- The length and height of each wall are given as 20m and 4m, respectively.
- The total area of the walls is the sum of the areas of all four walls: 2 * (length * height + width * height).
- Substituting the given values, we have: 2 * (20m * 4m + 15m * 4m).
2. Area of the ceiling:
- The ceiling is also a rectangle, with the same length and width as the floor.
- The area of the ceiling is given by length * width: 20m * 15m.
3. Area of the floor:
- The area of the floor is the same as the area of the ceiling: 20m * 15m.
Now, let's calculate the areas:
1. Area of the walls:
- 2 * (20m * 4m + 15m * 4m) = 2 * (80m^2 + 60m^2) = 2 * 140m^2 = 280m^2.
2. Area of the ceiling:
- 20m * 15m = 300m^2.
3. Area of the floor:
- 20m * 15m = 300m^2.
Next, we can calculate the number of tins of paint and tiles needed and their costs:
- Number of tins of paint needed = Area of walls / Coverage per tin = 280m^2 / 40m^2/tin = 7 tins.
- Cost of paint = Number of tins * Cost per tin = 7 tins * £15/tin = £105.
- Number of tiles needed = Area of floor / Area per tile = 300m^2 / 1m^2/tile = 300 tiles.
- Cost of tiles = Number of tiles * Cost per tile = 300 tiles * £3/tile = £900.
Therefore, the total cost of paint and tiles needed to decorate the community hall is £105 + £900 = £1005.
yes, i am a student