MATHEMATICS HIGH SCHOOL

In order to prove a conjecture is always true, you must show? A.) a formal proof
B.) a counterexample
C.) several true examples
D.) an informal proof

Answers

Answer 1

Answer:

In order to prove a conjecture is always true is formal proof.

We have given that,

A.) a formal proof

B.) a counter-example

C.) several true examples

D.) an informal proof

We have to prove a conjecture is always true

In order to prove a conjecture is always true, you must show formalproof.

What is the conjecture?

A conjecture is a conclusion or a proposition that is proffered on a tentative basis without proof.

Therefore the first option is correct.

In order to prove a conjecture is always true is formal proof.

To learn more about the conjecture visit:

brainly.com/question/2292059

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Answer 2

Answer:

Answer: A- a formal proof

Step-by-step explanation:

just is

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If the lateral edge of a regular tetrahedron is 8 cm, then it's altitude is?

Answers

Answer:

The altitude is 6.53 cm

Step-by-step explanation:

A regular tetrahedron is a triangular pyramid having equilateral triangular faces, therefore we have;

Sides of the equilateral triangle = 8 cm

Given that the slant height, the edge of the tetrahedron, and half the base edge of the tetrahedron form a right triangle, we have;

The slant height, h = √(8² - (8/2)²) = √48 = 4×√3

The segment representing the altitude, H, of the tetrahedron forms a right triangle with the edge of the tetrahedron and 2/3×h

Therefore;

8² = H² + (2/3×4×√3)²

H² = 8² - (2/3×4×√3)²

H² = 64 - 64/3 = 128/3

The altitude H = √(128/3) = √6×8/3 = 6.53 cm.

Plz answer rn nmmmm ASAP!!

Answers

Answer:

Step-by-step explanation:

12.6÷−4.2=
Please help meeeeeeeeeeee

Answers

Answer:

Step-by-step explanation:

12.6/4.2 = 3

Answer:-3

Step-by-step explanation:

Find the product of (x − 3)2.
x2 + 6x + 9
x2 − 9
x2 − 6x + 9
x2 + 9

Answers

(x-3)² ⇒ (x-3)(x-3)

(x-3)(x-3) = x(x-3) -3(x-3) ⇒ x² - 3x - 3x + 9 ⇒ x² - 6x + 9

The 3rd option is the correct answer. x² - 6x + 9

Answer:

$\large\boxed{x^2-6x+9}$

Step-by-step explanation:

$(x-3)^2\n\n\bold{METHOD\ 1}\n\n(x-3)^2=(x-3)(x-3)\qquad\text{use FOIL}\ (a+b)(c+d)=ac+ad+bc+bd\n\n=(x)(x)+(x)(-3)+(-3)(x)+(-3)(-3)\n\n=x^2-3x-3x+9\qquad\text{combine like terms}\n\n=x^2-6x+9\n\n\bold{METHOD\ 2}\n\n(x-3)^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\n\n=x^2-2(x)(3)+3^2\n\n=x^2-6x+9$