The area of the base of a prism is 50 mm2. The perimeter of the base is 30 mm. The height of the prism is 7 mm.What is the surface area of the prism?
mm2
Answers
surface area of a rectangular prism with a base length of 70 mm^2, perimeter of the base is 50 mm. The height of the prism is 9 mm. let a= base length, b = base width, c = height=9. a*b= 70. a+b+9=50, or a+b=41, now bc+ca= c(a+b)=9*41=369 so suface area= 2(ab+bc+ca)= 2(70+369)=878 mm^2
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.5(30)(7)
15*7= 105 mm
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What is the ratio of people who prefer oranges to bananas?
Answers
Then, you add the initial $1500,
which means he now has $5000
The difference between $5000 and $4500 is $500,
And $500 is 9% of $4500,
So the deal is equivalent to a yearly interest of 9%
Hope this helps ! :)
Answers
p1 - probability for outcome 1
p2 - probability for outcome 2
p3 - probability for outcome 3
v1 - amount of money that you will win or lose for outcome 1
v2 - amount of money that you will win or lose for outcome 2
v3 - amount of money that you will win or lose for outcome 3
Therefore,
p1v1 + p2v2 + p3v3 is the average money you win or lose in playing the game.
Answer:
Option b) The average amount you will win (or lose) per game in the long run
Step-by-step explanation:
Answers
Answer:
The length of the altitude CD is 3.3 units .
Option (D) is correct .
Step-by-step explanation:
By using the pythagorean theorem
Hypotenuse² = Perpendicular² + Base²
Now in ΔCDA
Hypotenuse = CA = 6 unit
Base = AD = 5 units
Perpendicular = CD
Put all the values in the above
6² = CD² + 5²
As
6² = 36
5² = 25
CD² = 6² - 5²
= 36 - 25
CD² = 11
CD = 3.3 unit (Approx)
Therefore the length of the altitude CD is 3.3 units .
Option (D) is correct .
hypotenuse=6
leg₁=5
leg₂=CD
Pythagoras theorem:
hypotenuse²=leg₁²+leg₂²
6²=5²+CD²
CD=√(6²-5²)
CD=√(36-25)
CD=√11≈3.3166....≈3.3
Answer: D. 3.3
What is the class width?
List the midpoints, relative frequency, and cumulative relative frequency
Make a relative frequency ogive
Make a frequency polygon
Calculate the mean
Calculate the median
Calculate the sample standard deviation (our data is sample from our class, not a population!)
Calculate the Q1 and Q3 values
Answers
The midpoints are calculated by adding the lower and upper limits of each class and dividing by 2. The midpoints for each class are: 20.5, 31.5, 42.5, 53.5, and 64.5.
The relative frequency is calculated by dividing the frequency of each class by the total number of data points (28 in this case). The relative frequencies for each class are: 0.1071, 0.1071, 0.2143, 0.2857, and 0.2857.
The cumulative relative frequency is calculated by adding up the relative frequencies for each class and all previous classes. The cumulative relative frequencies for each class are: 0.1071, 0.2143, 0.4286, 0.7143, and 1.
To make a relative frequency ogive, you would plot the cumulative relative frequencies against the upper limits of each class.
To make a frequency polygon, you would plot the midpoints of each class against their respective frequencies.
The mean is calculated by adding up all the data points and dividing by the total number of data points (28 in this case). The mean is approximately 32.39.
The median is calculated by finding the middle value when all the data points are arranged in order from smallest to largest. Since there are an even number of data points (28), we take the average of the two middle values (25 and 30). So, the median is (25+30)/2=27.5.
The sample standard deviation is calculated using the formula: sqrt(sum((x-mean)^2)/(n-1)), where x is each data point, mean is the mean of all the data points, n is the total number of data points (28 in this case). The sample standard deviation is approximately 12.87.
The Q1 value (the first quartile) is calculated by finding the median of the lower half of the data points (14 in this case). Since there are an even number of data points in this half (14), we take the average of the two middle values (22 and 22). So, Q1 is (22+22)/2=22.
The Q3 value (the third quartile) is calculated by finding the median of the upper half of the data points (14 in this case). Since there are an even number of data points in this half (14), we take the average of the two middle values (34 and 35). So, Q3 is (34+35)/2=34.5.
This mathematical question focused on descriptive statistics, such as calculating the class widths for a frequency distribution,
Determining the midpoints, relative frequency, and cumulative relative frequency, drawing a relative frequency ogive and frequency polygon, and calculating the mean, median, sample standard deviation, Q1, and Q3.First, to construct a frequency distribution with a total of 5 classes, we need to determine the class width. We get this by subtracting the smallest value from the largest value and dividing by the number of classes, then rounding up. In this case, (73-18)/5 = 11. Therefore, the class width is 11.Next, we calculate the midpoints of each class, relative frequency, and cumulative relative frequency. After that, we create the relative frequency and frequency polygon. Unfortunately, without a greater context, these cannot be shown here.For the mean, we sum up all the numbers and divide by the number of observations. In this case, the mean is the sum of the values divided by 29.We calculate the median, which is the middle value when the numbers are arranged in ascending order. For this dataset, the median would be the 15th data value.The sample standard deviation is a little more complex. It involves finding the mean, subtracting each value from the mean and squaring the result, summing these squared values, dividing by the number of observations minus 1, and taking the square root. This gives the sample standard deviation.Lastly, Q1 and Q3 are the 25th and 75th percentiles, respectively. Q1 and Q3 can be calculated by sorting the data in ascending order and taking the 25th and 75th percentile positions.
To know more about frequency visit :
#SPJ11
Answers
Answer:
Profit = Rs 100
Profit %age = 6.25%
Step-by-step explanation:
Cost Price = Rs 80
Cost Price for 20 kg = Rs 1600
Selling Price = Rs 85
Profit for 1 kg = Rs 85 - Rs 80
=> Rs 5 (For 1 Kg)
Profit for 20 kg:
=> Rs 5*20
=> Rs 100
Now Profit %age:
=>
=> 0.0625 * 100
=> 6.25%
Step-by-step explanation:
profit =S.P-C.P
C.P=20×80
=Rs1600
S.P=20×85
=Rs1700
=1700-1600
=Rs 100
=
Answers
Answer:
what is it
Step-by-step explanation: