A) Kenyans went elections and they had to choose between three coalitions; JubileeCord and Amani. They must choose one, if they have no preference, can choose
all the three or, if against one option, they choose for the two they prefer. A
sample of 200 voters revealed the following information
30 chose Jubilee and Amani but not Cord
130 chose Cord only
102 chose Amani only
30 chose Jubilee and Cord
234 chose for either Jubilee or Cord, or both Jubilee and Cord, but not Amani
256 chose for either Cord or Amani, or both Cord and Amani, but not Jubilee
How
many
students chose
i) All the three options
(2 marks
ii) Only one option
(2 marks
iii) Jubilee irrespective of Cord or Amani
(2 marks​

Answer:

Center is at (-4, -2) and the radius = 5.

Step-by-step explanation:

Convert to Standard form:

x^2 + 8x + y2 + 4y - 5= 0  

Completing the square:

(x + 4)^2 - 16 + (y + 2)^2 - 4 = 5

(x + 4)^2 + (y + 2)^2  = 5 + 16 + 4

(x + 4)^2 + (y + 2)^2  = 25

(x - h)^2 + (y - k)^2 = r^2     Comparing:-

The center is at (-4, -2) and the radius = 5.

Answer:

The number is  

Step-by-step explanation:

From the question we are told that  

      The sample size is  n =  800

       The number of seniors is  S  =  519

         The number of  commuters is  C =  430

         The number of of seniors that are commuters is  

Generally the number of 800 surveyed students who were seniors or were commuters is  mathematically evaluated as

=>  

=>  

Answer:

50%

Step-by-step explanation:

Let :

Winter = W

Summer = S

P(W) = 0.85

P(S) = 0.65

Recall:

P(W u S) = p(W) + p(S) - p(W n S)

Since, none of them did not like both seasons, P(W u S) = 1

Hence,

1 = 0.85 + 0.65 - p(both)

p(both) = 0.85 + 0.65 - 1

p(both) = 1.50 - 1

p(both) = 0.5

Hence percentage who like both = 0.5 * 100% = 50%

Answer:

12 blue necklaces + 12 red necklaces = 24 necklaces. He will have 1 blue bead left over and 1 red bead left over.

Step-by-step explanation:

37/3 = 12.333 or 12 r1

25/2= 12.5 or 12 r1

1+1=2

Answer:

wire for square to maximize total area = 23 m

Wire to minimize total area = 2.019 m

Step-by-step explanation:

For the square, let's say the total length of the square is "y" m.

Thus, length of one side is = y/4

And area of the square = (y/4) = y²/16

Since the wire is 23 m, then total length of equilateral triangle is; 23 - y.

Thus, length of one side of equilateral triangle = (23 - y)/3

Using trigonometric ratio, we can find the height of the triangle and thus area.

Area of triangle = (√3)/4) × ((23 - y)/3)²

Area of triangle = (√3)/36)(23 - y)²

So, total area of square and triangle is;

A_total = (y²/16) + (√3)/36)(23 - y)²

Now, extremizing this function by derivatives, we have;

dA/dy = (y/8) - (√3)/18)(23 - y)

d²A/dy² = ⅛ + (√3)/18)

So, d²A/dy² > 0

Now,let's find the maximum or minimum of the function.

So, we equate dA/dy to zero.

Thus;

(y/8) - (√3)/18)(23 - y) = 0

y/8 = (√3)/18)(23 - y)

(y/8) + (√3)/18)y = 23((√3)/18)

Multiply through by 8 to give;

y + 0.0962y = 2.2132

1.0962y = 2.2132

y = 2.2132/1.0962

y = 2.019 m

2.019 will be a minimum because d²A/dy² > 0

The maximum will occur at a boundary of the allowed values. Thus, the absolute maximum is for y = 23.

Note that a square has more area than a triangle and as such it is normal for the square to get the largest area over the triangle and therefore we will have to use all of the wire to construct the square.