Which statements accurately describe matter

Answers

Answer 1

Answer:

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Related Questions

Two objects are traveling on the same track. for 10 s, object x has an average acceleration of 3.0 m/s/s. if object y has an initial velocity of 0 m/s and a final velocity of 25 m/s after 10 s, how does it acceleration compared to object x's?
A ball is thrown horizontally from the top ofa building 140 m high. The ball strikes the ground 54 m horizontally from the point of release. What is the speed of the ball just before it strikes the ground? Answer in units of m/s.
In a science museum, a 130 kg brass pendulum bob swings at the end of a 14.4 m -long wire. The pendulum is started at exactly 8:00 a.m. every morning by pulling it 1.7 m to the side and releasing it. Because of its compact shape and smooth surface, the pendulum's damping constant is only 0.010kg/s. You may want to review (Pages 405 - 407) . Part A At exactly 12:00 noon, how many oscillations will the pendulum have completed
Why do scientist use classification
The tendency of an object to resist any change in its motion is known as?

Scientists have found ancient rock formations dating to the late Proterozoic eon in South America. These ancient rocks can be found from the eastern edge of South America's continental shelf, which extends just off the coast of Brazil, to the interior of the continent. This general location is indicated by a green circle on the map below. Scientists have also found rock formations made out of the same type of rock and from the very same eon at another location. The location of this second group of rock formations strongly supports the current theory of plate tectonics.

Where is the second rock formation most likely located?

Answers

Answer:

that not the answer the answer is off the cost of Africa

Explanation:

Answer: Australia

Explanation:

A material that transmits nearly all the light in a ray because it offers little resistance to the light is A. translucent.
B. opaque.
C. fluorescent.
D. transparent.

Answers

Answer

D. transparent.

Explanation.

Materials can be classified into three in relation to how light pass through them.

Translucent. These are materials that allow light to pass through them but you can not see through them. A good example of this material is the glass that is used to make doors of a bathroom.

Opaque. These are material that cannot at all allow light to go through them. Examples are; Thick metals, concrete, wood and many others.

Transparent. Theses are materials that allow light to go through them and also you can see through them. A good example is the windscreen of a car.

With this information the correct answer is D. transparent.

The answer is D, transparent

As a bat flies toward a wall at a speed of 6.0 m/s, the bat emits an ultrasonic sound wave with frequency 30.0 kHz. What frequency does the bat hear in the reflected wave?

Answers

Answer:

$f_b = 29.98 Hz$

Explanation:

speed of bat = 6 m/s

sound wave frequency emitted by bat = 30.0 kHz

as we know,

speed of sound (c)= 343 m/s

$f_w = f((c+v_r)/(c+v_s))$

$f_w = 30((343+0)/(343+6))$

$f_w = 29.48 Hz$

now frequency received by bat is equal to

$f_b = f((c+v_r)/(c+v_s))$

$f_b = 29.48((343+6)/(343+0))$

$f_b = 29.98 Hz$

hence the frequency hear by bat will be 29.98 Hz

Final answer:

The Doppler effect represents the change in frequency of a wave due to the motion of the source or the observer. In this case, the bat hears a higher frequency because of its motion towards the wall and the reflection of the sound wave back towards it.

Explanation:

The question is asking for the frequency the bat hears when it emits a sound and the sound is reflected back after hitting a wall. This is an example of the Doppler effect, where the frequency of a wave changes for an observer moving relative to the source of the wave.

Let's denote the emitted frequency as f (30.0 kHz), the speed of the bat as v (6.0 m/s), and the speed of sound in air as v_s (approximately 343 m/s).

First, when the bat emits the ultrasonic wave, the frequency of the wave will increase because of the motion of the bat towards the wall. The formula for observed frequency (f') when source and observer are getting closer is given by f' = f * (v_s + v) / v_s.

Next, the wall will reflect this wave back towards the bat. Since the wave is moving towards the bat, the frequency will increase again by the same factor, resulting in a final observed frequency of f'' = f' * (v_s + v) / v_s. When you substitute f' into this equation, you'll get: f'' = f * (v_s + v)^2 / v_s^2

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What is the strength of the electric field 0.020 m from a 12 µC charge?

Answers

The electric field strength at a distance of 0.020 m from a 12 µC point charge is approximately 2.69 x 10⁸ N/C.

What is the electric field strength?

The electric field strength (E) at a point near a point charge is given by the equation:

E = k Q / r²

where:

k is Coulomb's constant, equal to 8.99 x 10⁹ Nm²/C²

Q is the magnitude of the point charge in coulombs

r is the distance from the point charge

Substituting the given values:

Q = 12 x 10⁻⁶ C

r = 0.020 m

E = k Q / r²

E = 8.99 x 10⁹ Nm²/C² x 12 x 10⁻⁶ C / (0.020 m)²

E = 2.69 x 10⁸ N/C

So the electric field strength at a distance of 0.020 m from a 12 µC point charge is approximately 2.69 x 10⁸ N/C.

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E = ko * C / d^2 = [9.0x10^9 N/m^2C^2 ]* [12x10^-6C]/[(0.020m)^2] = 2.7^10^8N/C

Work is being done in which of these situations? all motions are at a constant velocity

Answers

Where the force is not perpendicular to the path of motion

are you missing the the situations ?

The greater the___of the object, the greater the force needed to achieve the same change in motion.

Answers

Answer:mass

Explanation:

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