Answer:
The time in which the pendulum does a complete revolution is called the period of the pendulum.
Remember that the period of a pendulum is written as:
T = 2*pi*√(L/g)
where:
L = length of the pendulum
pi = 3.14
g = 9.8 m/s^2
Here we know that L = 14.4m
Then the period of the pendulum will be:
T = 2*3.14*√(14.4m/9.8m/s^2) = 7.61s
So one complete oscillation takes 7.61 seconds.
We know that the pendulum starts moving at 8:00 am
We want to know 12:00 noon, which is four hours after the pendulum starts moving.
So, we want to know how many complete oscillations happen in a timelapse of 4 hours.
Each oscillation takes 7.61 seconds.
The total number of oscillations will be the quotient between the total time (4 hours) and the period.
First we need to write both of these in the same units, we know that 1 hour = 3600 seconds
then:
4 hours = 4*(3600 seconds) = 14,400 s
The total number of oscillations in that time frame is:
N = 14,400s/7.61s = 1,892.25
Rounding to the next whole number, we have:
N = 1,892
The pendulum does 1,892 oscillations between 8:00 am and 12:00 noon.
The question involves the concept of a simple pendulum whose number of swings is largely influenced by its length and the acceleration due to gravity. By determining the period of the pendulum, one can figure out the number of oscillations over a given time period. The pendulum's damping constant is negligible in determining the number of oscillations.
The subject of this question involves understanding the concept of a simple pendulum and how it relates to harmonic motion. It is widely known that the mass of the pendulum does not influence the oscillations but rather the length of the pendulum wire and acceleration due to gravity are paramount.
First, the necessary step toward calculating the number of swings would be to calculate the period of the pendulum's oscillation. This is given by the formula T=2*π*sqrt(L/g), where L is the length of the pendulum (14.4m) and g is the acceleration due to gravity (~9.81m/s²). Substituting these values will give us the period, T, in seconds.
The pendulum starts swinging at 8:00 am and at 12:00 noon, 4 hours or 14400 seconds will have passed. Therefore the number of oscillations will be calculated by dividing the total time by one period of oscillation.
It is crucial to note that the damping in this instance is quite small and would not significantly affect the number of oscillations.
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The Objects separated by gravitational force of 360 N, masses 6.25 × 10¹⁴ kg and 7.20 × 10⁵ kg. Applying Newton's law with G = 6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻² yields distance is 2.79139 km.
We can apply Newton's law of universal gravitation to calculate the distance between the two objects. The formula takes the form:
F = (G ⋅ m₁ ⋅ m₂) / r²
Where:
F represents the force between the two objects
G stands for the gravitational constant (6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻²)
m₁ and m₂ denote the masses of the two objects
r indicates the distance between the centers of the two objects
Given that the force F = 360 N, m₁ = 6.25 × 10¹⁴ kg, and m₂ = 7.20 × 10⁵ kg, we can solve for r:
r² = (G ⋅ m₁ ⋅ m₂) / F
r = √((G ⋅ m₁ ⋅ m₂) / F)
Now, substituting the values and solving for r:
r = √(((6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻²) ⋅ (6.25 × 10¹⁴ kg) ⋅ (7.20 × 10⁵ kg)) / 360 N)
r ≈ 2791.39 m
Finally, converting the distance from meters to kilometers:
r ≈ 2.79139 km
Consequently, the two objects are approximately 2.79139 kilometers apart.
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#SPJ11
b. 48.91 s
c. 48.910 s
d. 48.9 s
Answer:
Least precise recorded time is 48.9 seconds.
Explanation:
Here, we need to write the recorded time that is least precise. The given options are (a) 48.9107 s (b) 48.91 s (c) 48.910 s (d) 48.9 s. The precision in any measurement is defined as closeness in any measurement.
First option is most precise as it is precised to four decimal places. Second option is precised to two decimal places. Third option is precised to 3 decimal places. But in option fourth, the recorded time is precised to one decimal place.
Hence, the correct option is (d).
Answer:
This is a Upside down Glass of Water Experiment
Explanation:
Explanation:
if I interpret the graphic correctly, then there is a basin fully filled with water on the left, then a piece of paper of a piece of glass, where the paper is in contract with the water on the left, and some water is delivered to the right.
then i suspect this shows the capillary effect of very narrow channels of water. like in the very tiny spaces between the fibers of the paper. as long as the paper is in contact with the water on the left, and the level of water is there higher than on the right, the surface tension of water kind of propels itself further along these narrow channels in the paper and supported by gravity and air pressure it drops even into the other side.