What is 6 1/2 / 3 1/2? please help me!

Answers

Answer 1
Answer:

Answer:

13/7 or 16/7, they are the same, just different ways of writing it.

Step-by-step explanation:

(6 1/2) / (3 1/2)

Convert to an improper fraction

(13/2) / (7/2)

To divide a fraction, find the  reciprocal of the second fraction, and multiply it by the first:

(13/2) * (2/7)

simplfiy

(13/7)

Which is the same as:

1 6/7

Answer 2
Answer:

Answer:

1 6/7

Step-by-step explanation:


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The conversion of square feet to square yards can be represented by direct variation. Three square yards are equivalent to 27 square feet. Let y represent the number of square yards and x the number of square feet. Then y varies directly with x.What is the constant of variation?
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9. If the area of a rectangle measures 20 square inches, the side lengthsmust be 4 inches and 5 inches.

Answers

Answer:

True

Step-by-step explanation:

The given statement is true.

Area of a rectangle is length times width.

A rectangle with the side length of 4 and 5 inches would have an area of 20 square inches.

A=l*w\n\nA=4*5\n\nA=20

Hope this helps.

Answer:

False

Step-by-step explanation:

There can be two sets of side lengths 4, 5 inches and 2, 10 inches.

If (m, 1) is on a circle with center (8, 1) and radius 7, what is a value of m?A)m=1
B)m=-1
C)m=14
D)m=-8=-+sqrt33

Answers

A) m=1

The equation for the circle is:

(x-8)^2 + (y-1)^2 = 49

If we take 'y' as 1, then

(x-8)^2 + 0 = 49

x-8 = √49

x = ±7 + 8

x = 15 or x = 1

2 × 10 + 10 – 8 = ? show work

Answers

2 x 10 = 20
10 - 8 = 2
20 + 2 = 22
Answer: Umm, 2 x 10+10-8=22

2 x 10=20
20+10=30
30-8=22

Which of the following functions have graphs that contain no asymptotes? select all that apply

Answers

Answer:

The power function and the root function

Step-by-step explanation:

Let's consider each function in turn.

Power function

y = xⁿ

For every value of x, there is a corresponding value of y.

There are no asymptotes.

Reciprocal

y = 1/x

The y-axis is an asymptote, because x cannot equal 0. y ⟶ ∞ as x ⟶ 0₊ and y ⟶ -∞ as x ⟶ 0₋

Similarly, the x-axis is an asymptote, because there is no finite value of x for which y = 0.

Exponential

y = b^(x)

The x-axis is an asymptote, because y can never be negativeand y ⟶ 0

as x ⟶ -∞.

Logarithmic

y = \text{log}_(b)(x)

The y-axis is an asymptote, because x cannot be negative and logx ⟶ -∞ as x ⟶ 0.

Root

y = \sqrt[5]{x}

There can be no negative value of x, but there is a value of y for every positive value of x.

Thus, there is no asymptote.

The power function and the root function have no asymptotes.

Answer:

Step-by-step explanation:

The graph of the power function has no asymptotes.  Check this one.

The graph of the reciprocal function DOES have asymptotes, both vertical and horizontal.  Do not check this function.

The graph of an exponential function has one asymptote, which is the line y = 0 (that is, the x-axis).  Do not check this function.

The graph of a log function has one asymptote, which is the line x = 0 (that is, the y-axis).  Do not check this function.

The root function does not have asymptotes.  Check this function.

What’s the measure of ACD

Answers

Answer:

option H, 130°

Step-by-step explanation:

In order to find the measure of ∠ACD, first find the measure of ∠ACB

∠ACB + ∠ABC + ∠BAC = 180° (angle sum property of a triangle)

∠ACB + 95° + 35° = 180°

∠ACB + 130° = 180°

∠ACB = 180° - 130°

∠ACB = 50°

∠ACD + ∠ACB = 180° (linear pair)

∠ACD + 50° = 180°

∠ACD = 180° - 50°

∠ACD = 130°

therefore, option H is the correct option

hope it helps you!

You have 60 marbles in a jar, two of which are red. (so 2 red, 58 not red)You pick 10 at random. What is the chance that you draw both red marbles?
Explanation please, not just the answer. Brainliest answer if you calculate it for 2 out of 251 total marbles as well.

Answers


Well, I agonized over this for a while, and I have something that we may want to consider.

The only probability formula I know how to use is

 Probability = (number of possible successes) / (total number of possibilities).

Can we work with that ?  Let's see . . .

The denominator of that fraction is the total number of ways to draw
10 marbles from a jar of 60 . . .

The first draw can be any one of 60 marbles. For each of those . . .
The second draw can be any one of the remaining 59.  For each of those . . .
The third draw can be any one of the remaining 58.
.
.
etc.

So the total number of ways to draw 10 from 60 is

       (60 x 59 x 58 x 57 x 56 x 55 x 54 x 53 x 52 x 51)

That's a very big number.  My calculator says something that rounds to
2.736 x 10¹⁷. But my calculator only shows 10 digits, so it can't show
all 18 digits in the number.  Fortunately, we don't need to see the whole
number written out.  We'll just write it in factorial notation, and go on
to do the numerator of the fraction, which is going to be much harder.

That number that we just found is equal to  (60!) / (50!) .  It's going to be
the denominator of the big fraction.

Now for the numerator.  That's going to be the number of ways that the
two red marbles can be included among the ten marbles drawn.

One red marble can be any one of the 10 marbles pulled out.
       For each of those . . .
The other red marble can be any one of the other 9 that are picked.

So there are (10 x 9) = 90 ways for the selected 10 to include both red ones.

SO !  Now, the probability that the ten that are drawn will include the two
red ones should be (it might be, it could be) . . .

             90 divided by  (60! / 50!)   .

Remember, that fraction on the right is just total number of ways
to pick 10 out of 60 .  The probability of including both red ones 
in the draw is  90 divided by that number.  It's very small.

Again from my calculator, it's    3.29 x 10⁻¹⁴ percent.

I have no confidence in my answer, but I invite you to look it over, along with
all the real gurus out there. 

If I'm wrong, then I've stolen only 5 points that I'm not entitled to, and at least
I did put some effort into it.

Here you have two proportions. 2/60 and 10/60. I would cross multiply. 
Giving you 20/120.
Simplify that to get 1/6. So you have a 1 in 6 chance of getting both the red marbles.
(I'm not 100% sure since it's been a while so you might want to get a second opinion.) 
Not sure what you mean by the second part, but hope I provided some help :)