Answer:
constant of variation is 1/9 and equation is y=1/9x
Step-by-step explanation:
3/27 = 1/9
Answer:
5+ 4x > 7, x > 1/2
Step-by-step explanation:
we know that
A mixed number is a number consisting of a whole number and a proper fraction
so
we have
therefore
the answer is
The value of mixed number of number 8.21 is,
⇒ 8 (21 / 100)
We have to given that;
A number is,
⇒ 8.21
Now, We can simplify as;
⇒ 8.21
⇒ 8.21 × 100 / 100
⇒ 821 / 100
⇒ 8 21/100
Therefore, The value of mixed number of number 8.21 is,
⇒ 8 (21 / 100)
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16Pi units squared
20Pi units squared
Answer:
" units squared"
Step-by-step explanation:
The image of the circle is attached.
The shaded area of the circle is basically HALF of the whole circle. If we can get the area of the circle, we will halve it, to get our answer for area of shaded region.
Area of circle is given as:
Where
A is area
r is the radius
Looking at the pic, the radius is "4", so we substitute and find area of circle:
THe shaded area is HALF of that, so:
Area of Shaded = sq. units.
Answer is " units squared"
Answer:
its 8
Step-by-step explanation:
i got it right
Answer:
AA, AD, AC, AB (or flipped)
BB, BD, BC, BA (or flipped)
CD, CA, CB, CC (or flipped)
DA, DC, DD, DB (or flipped)
Step-by-step explanation:
a) an = 6an-1, a0 = 2
b) an = −2an-1, a0 = −1
c) an = an-1 – an-2, a0 = 2, a1 = −1
a) The first five terms of the sequence are 2, 12, 72, 432, 2592.
b) The first five terms of the sequence are -1, 2, -4, 8, -16.
c) The first five terms of the sequence are 2, -1, -3, -2, 1.
To find the first five terms of the sequence defined by each of these recurrence relations and initial conditions, we will use the given recurrence relation and initial conditions to find the next terms in the sequence.
a) an = 6an-1, a0 = 2
The first term is given as a0 = 2. We will use the recurrence relation to find the next terms.
a1 = 6a0 = 6(2) = 12
a2 = 6a1 = 6(12) = 72
a3 = 6a2 = 6(72) = 432
a4 = 6a3 = 6(432) = 2592
So, the first five terms of the sequence are 2, 12, 72, 432, 2592.
b) an = −2an-1, a0 = −1
The first term is given as a0 = -1. We will use the recurrence relation to find the next terms.
a1 = -2a0 = -2(-1) = 2
a2 = -2a1 = -2(2) = -4
a3 = -2a2 = -2(-4) = 8
a4 = -2a3 = -2(8) = -16
So, the first five terms of the sequence are -1, 2, -4, 8, -16.
c) an = an-1 – an-2, a0 = 2, a1 = −1
The first two terms are given as a0 = 2 and a1 = -1. We will use the recurrence relation to find the next terms.
a2 = a1 - a0 = -1 - 2 = -3
a3 = a2 - a1 = -3 - (-1) = -2
a4 = a3 - a2 = -2 - (-3) = 1
So, the first five terms of the sequence are 2, -1, -3, -2, 1.
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