b. 0.1
c. 0.7
d. 1.2
(PLEASE EXPLAIN HOW YOU RECEIVED YOUR ANSWER)
Answer:
3
Step-by-step explanation:
Rewriting this sentence as an algebraic equation, we get:
3^10 = 3^7 * x^3.
Dividing both sides by 3^7 simplifies the problem:
3^3 = x^3
Here this x corresponds to the 3 in 3^3. Thus, the solution is x = 3.
Using exponent rules and logarithms, the given equation can be simplified and solved to find that x equals 3.
The subject of the question falls into the field of Mathematics, specifically exponent rules, which are used in High School level algebra. In the mathematics problem provided ('3 to the 10th power = 3 to the 7th power times x to the 3rd power'), we need to solve for x using the knowledge of exponents.
First, it's helpful to know that when two expressions with the same base (in this case, 3) are set equal to each other, their exponents must also be equal. Since we know that 3 to the 7th power times x to the 3rd power equals 3 to the 10th power, we can break this down further. This leads to the equation 7 + 3log(x) = 10, where 'log' represents the logarithm.
By simplifying the equation, we get 3log(x) = 10-7, so 3log(x) = 3. Therefore, log(x)=3/3, hence log(x)=1. If we apply anti logarithm on both sides, we'll find that x = 3 to the power of 1, so x = 3. In other words, 3 to the 3rd power will equal3 to the 10th power divided by 3 to the 7th power. Hence, the value of x is 3.
#SPJ3
Answer:
Rhombus
Step-by-step explanation:
We are given that Victor drew a quadrilateral with no right angles and 4 sides of equal length.
We have to find that what type of quadrilateral Victor could have drawn
We know that
A quadrilateral in which four sides of equal length can be square or rhombus.
But in square all angles of square are right angles.But Victor draw a quadrilateral in which no right angles .Therefore, the quadrilateral drawn by Victor could be rhombus because in rhombus all sides of equal length but no right angles.
A square can be rhombus but rhombus can not be square .Hence, the quadrilateral drawn by Victor is a rhombus .
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