MATHEMATICS COLLEGE

How much of a 3/4 of cup serving is in a 2/3 cup of yogurt?

Answers

Answer 1

Answer:

Answer:

8/9

Step-by-step explanation:

could i have brailiest plz it isnt a must tho thx

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What is the quotient of 75,120 ÷ 16?

Answers

Answer:

4695

Step-by-step explanation:

Answer:

4,695

use long divison

Find the zeros of the function
k(x) = -5x² - 125
The zeros of k are x= □ and x= □

Answers

Answer:

x = ±5i

General Formulas and Concepts:

Pre-Alg

Order of Operations: BPEMDAS

Alg II

√-1 is imaginary number i

Step-by-step explanation:

Step 1: Define function

k(x) = -5x² - 125

Step 2: Find roots

Set function equal to 0: 0 = -5x² - 125
Factor out -5: 0 = -5(x² + 25)
Divide both sides by -5: 0 = x² + 25
Subtract 25 on both sides: -25 = x²
Rewrite: x² = -25
Square root both sides: x = ±√-25
Rewrite: x = √-1 · ±√25
Evaluate: x = ±5i

There were 5,317 previously owned homes sold in a western city in the year 2000. The distribution of the sales prices of these homes was strongly right-skewed, with a mean of $206,274 and a standard deviation of $37,881. If all possible simple random samples of size 100 are drawn from this population and the mean is computed for each of these samples, which of the following describes the sampling distribution of the sample mean? (A) Approximately normal with mean $206,274 and standard deviation $3,788
(B) Approximately normal with mean $206,274 and standard deviation $37,881
(C) Approximately normal with mean $206,274 and standard deviation $520
(D) Strongly right-skewed with mean $206,274 and standard deviation $3,788
(E) Strongly right-skewed with mean $206,274 and standard deviation $37,881

Answers

Approximately normal with mean is $206,274 and standard deviation is $3,788 and this can be determined by applying the central limit theorem.

Given :

There were 5,317 previously owned homes sold in a western city in the year 2000.
The distribution of the sales prices of these homes was strongly right-skewed, with a mean of $206,274 and a standard deviation of $37,881.
Simple random samples of size 100.

According to the central limit theorem the approximately normal mean is $206274.

Now, to determine the approximately normal standard deviation, use the below formula:

$s =(\sigma )/(√(n) )$ ---- (1)

where 's' is the approximately normal standard deviation, 'n' is the sample size, and $\sigma$ is the standard deviation.

Now, put the known values in the equation (1).

$s = (37881)/(√(100) )$

s = 3788.1

$\rm s \approx 3788$

So, the correct option is A).

For more information, refer to the link given below:

brainly.com/question/18403552

Answer:

(A) Approximately normal with mean $206,274 and standard deviation $3,788

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = (\sigma)/(√(n))$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Population:

Right skewed

Mean $206,274

Standard deviation $37,881.

Sample:

By the Central Limit Theorem, approximately normal.

Mean $206,274

Standard deviation $s = (37881)/(√(100)) = 3788.1$

So the correct answer is:

(A) Approximately normal with mean $206,274 and standard deviation $3,788

The use of social networks has grown dramatically all over the world. In a recent sample of 24 American social network users and each was asked for the amount of time spent (in hours) social networking each day. The mean time spent was 3.19 hours with a standard deviation of 0.2903 hours. Find a 99% confidence interval for the true mean amount of time Americans spend social networking each day

Answers

Answer:

The 99% confidence interval for the true mean amount of time Americans spend social networking each day is (3.02 hours, 3.36 hours).

Step-by-step explanation:

The (1 - α)% confidence interval for population mean when the population standard deviation is not known is:

$CI=\bar x\pm t_(\alpha/2, (n-1))* (s)/(√(n))$

The information provided is:

$n=24\n\bar x=3.19\ \text{hours}\ns=0.2903\ \text{hours}$

Confidence level = 99%.

Compute the critical value of t for 99% confidence interval and (n - 1) degrees of freedom as follows:

$t_(\alpha/2, (n-1))=t_(0.01/2, (24-1))=t_(0.005, 23)=2.807$

*Use a t-table.

Compute the 99% confidence interval for the true mean amount of time Americans spend social networking each day as follows:

$CI=\bar x\pm t_(\alpha/2, (n-1))* (s)/(√(n))$

$=3.19\pm 2.807* (0.2903)/(√(24))\n\n=3.19\pm 0.1663\n\n=(3.0237, 3.3563)\n\n\approx (3.02, 3.36)$

Thus, the 99% confidence interval for the true mean amount of time Americans spend social networking each day is (3.02 hours, 3.36 hours).

How many pairs of skis in stock does the shop have to have to make the probability in question 4 less than .01? Round your answer to a whole numbermean=150
Standard Deviation=20

Answers

Answer:

159 hwqb Step-by-step explanation:2n3wq,brudj32nwqrdb3wndj32wsd

Change 3 5/8 into an improper fraction.

Answers

The fractions is solved and the improper fraction is A = 29/8

Given data ,

To change 3 5/8 into an improper fraction, we need to combine the whole number and the fraction part.

The fraction part, 5/8, can be expressed as an improper fraction by multiplying the whole number, 3, by the denominator of the fraction, 8, and then adding the numerator, 5. This gives us:

3 * 8 + 5 = 24 + 5 = 29

The denominator remains the same, so the improper fraction is:

A = 29/8

Therefore , the value of A = 29/8

Hence , 3 5/8 can be expressed as the improper fraction 29/8

To learn more about fractions click :

brainly.com/question/29766013

#SPJ6

Answer:

The improper fraction 29/8 is equal to the mixed number 3 5/8.

Step-by-step explanation:

Other Questions

Let X1, X2, and X3 represent the times necessary to perform three successive repair tasks at a service facility. Suppose they are normal random variables with means of 50 minutes, 60 minutes, and 40 minutes, respectively. The standard deviations are 15 minutes, 20 minutes, and 10 minutes, respectively. a Suppose X1, X2, and X3 are independent. All three repairs must be completed on a given object. What is the mean and variance of the total repair time for this object.

The value of the Euler \phi function (\phi is the Greek letter phi) at the positive integer n is defined to be the number of positive integers less than or equal to n that are relativel prime to n, For example for n=14, we have {1, 3, 5, 9, 11, 13} are the positive integers less than or equal to 14 which are relatively prime to 14. Thus \phi (14) = 6.Find the following:\phi(9) = __________.\phi(15) = __________.\phi(75) =__________.

Random samples of size 17 are taken from a population that has 200 elements, a mean of 36, and a standard deviation of 8. Which of the following best describes the form of the sampling distribution of the sample mean for this situation? a. Approximately normal because the sample size is small relative to the population size b. Approximately normal because of the central limit theorem c. Exactly normal d. None of these alternatives is correct.

Math help!!! Who know the answers???