Random samples of size 17 are taken from a population that has 200 elements, a mean of 36, and a standard deviation of 8. Which of the following best describes the form of the sampling distribution of the sample mean for this situation? a. Approximately normal because the sample size is small relative to the population size b. Approximately normal because of the central limit theorem c. Exactly normal d. None of these alternatives is correct.

Answers

Answer 1
Answer:

None of the given alternatives described the Sample mean for the situation. A complete solution is below.

Given values are:

Sample size,

  • n = 17

Mean,

  • μ = 36

Standard deviation,

  • σ = 8

As we know,

The Standard deviation of sample mean,

(\sigma)/(√(n) )

By substituting the values, we get

(8)/(√(17) )

(8)/(4.13)

1.94

Thus the response i.e., "option d" is appropriate.

Learn more:

brainly.com/question/16555520

Answer 2
Answer:

Answer:

d

Step-by-step explanation:


Related Questions

Which postulate or theorem would you use to prove these two triangles congruent?
Please help!! Will give 20 points!​
The Westwood Warriors basketball team wants to score more points. To get better at scoring points the team is trying to improve its offensive strategies. Some opponents primarily use a zone defense, while others primarily use a man-to-man defense. When the Warriors play against teams that use a zone defense they score an average of 67 points per game with a standard deviation of 8 points per game. When they used a new offensive strategy against this defense, they scored 77 points. What is the Z-score of this value
HURRY IM TIMED ON EDGE Which is the best estimate for the percent equivalent to 3/8?26%279%37%38%
Determine the slope and y-intercept from the following equationy = (32) x + 3

Equivalent ratio of 30:36=5:_

Answers

30:36 is equivalent to 5:6
30:36 (divide by 6) = 5:6 
56:36 (divide by 4) = 14:9 
15:18:9 (divide by 3) = 5:6:3 

When solving ratios divide by greatest common factor of the numbers(GCF). 

Example: 2:4:6 
GCF=2 
Divide by 2 
Answer=1:2:3 

I hope this was helpful to you!

Show the tens fact you used. Write the difference.
16-9=
10-___=_____

Answers

16-9=7 and 10-9=2 and that's the answer

Write the expression multiply 0.035 times of a power of 10 so that the product is greater than one by less than 100

Answers

Answer:

0.035* 10^(3)

0.035* 10^(2)

Step-by-step explanation:

Given the number: 0.035 which has three decimal place

  • Case 1:  if we multiply  by 10

=> we have: 0.035*10 = 0.35

Hence, the product 0.35 which is smaller than 1 (we do not accept)

  • Case 2:  if we multiply  by 1000

=> we have: 0.035*1000 = 35

Hence, the product 35 which is greater than 1 and less than 100

  • Case 3:  if we multiply  by 100

=> we have: 0.035*100= 3.5

Hence, the product 3.5 which is greater than 1 and less than 100

  • Case 4:  if we multiply  by 10000

=> we have: 0.035*10000= 350

Hence, the product 350 which is greater than 100 (we do not accept)

Therefore, we have two expression:

0.035* 10^(3)

0.035* 10^(2)

17
Σ (15 – 9n)
η = 4

Answers

Answer:

  -1113

Step-by-step explanation:

You apparently want the sum of the 14-term arithmetic sequence ...

  -21, -30, -39, ..., -138

The average term is ...

  (-21 -138)/2 = -79.5

so the sum of the 14 terms is ...

  (14)(-79.5) = -1113

                                17

                                  Σ (15 – 9n)  = -1113

                                 η = 4

  • nth term

                         aₙ = 15 - 9n

        a₄ = 15-9*4 = 15-36= -21

       a₁₇ = 15 - 9(17) = -138

  • Sum;

                      S = (a₁ + aₙ)*n/2

         n = 14

         a₁ = a₄= -21

         aₙ = a₁₇ = -138

                   S = (-21 - 138)*14/2

                   S = -1113

Help.........idk..........

Answers

1=Osle because its lower in C than the other city

2=-12 because its below not above

3=28 because its above not below Hope this helps

Answer:

1=Osle because its lower in C than the other city

2=-12 because its below not above

3=28 because its above not below Hope this helps

Step-by-step explanation:

WILL MARK BRAINLIEST PLEASE HELP!!!A right circular cone is intersected by a plane that passes through the cone's vertex and is parallel to its base, as in the picture below. What is produced from this intersection?

A. A Pair of intersecting lines
B. A Parabola
C. A Point
D. A Pair of parallel lines

Answers

Answer:its D. A pair of parallel lines

Step-by-step explanation:

Answer: parallel lines

Step-by-step explanation:

Other Questions
Consider a random sample of ten children selected from a population of infants receiving antacids that contain aluminum, in order to treat peptic or digestive disorders. The distribution of plasma aluminum levels is known to be approximately normal; however its mean u and standard deviation o are not known. The mean aluminum level for the sample of n = 10 infants is found to be X = 37.20 ug/l and the sample standard deviation is s = 7.13 ug/1. Furthermore, the mean plasma aluminum level for the population of infants not receiving antacids is known to be only 4.13 ug/1.(a) Formulate the null hypothesis and complementary alternative hypothesis, for a two-sided test of whether the mean plasma aluminum level of the population of infants receiving antacids is equal to the mean plasma aluminum level of the population of infants not receiving antacids.(b) Construct a 95% confidence interval for the true mean plasma aluminum level of the population of infants receiving antacids.(c) Calculate the p-value of this sample (as best as possible), at the a=.05 significance level.(d) Based on your answers in parts (b) and (c), is the null hypothesis rejected in favor of the alternative hypothesis, at the a = .05 significance level? Interpret your conclusion: What exactly has been demonstrated, based on the empirical evidence?(e) With the knowledge that significantly elevated plasma aluminum levels are toxic to human beings, reformulate the null hypothesis and complementary alternative hypothesis, for the appropriate one-sided test of the mean plasma aluminum levels. With the same sample data as above, how does the new p-value compare with that found in part (c), and what is the resulting conclusion and interpretation?