Answer:
Energy is given off or absorbed.
Explanation:
A P E X
1
3
2
4
Answer:
2 Works on OW 2021
Explanation:
(B)multiple orbitals of specific magnitude within an energy level
(C)only those energy levels that overlap others
(D)electrons whose energy has dropped to a lower state
Answer:
Option B
Explanation:
First, we need to know what is an energy level.
An energy level corresponds to the row of the periodic table of element. So, if you see the attached picture, you can see that we have 7 rows where the elements are distributed, so, we have 7 energy levels for all those elements.
Knowing that, the sub levels are the caps where the electrons of the atoms are carried. These sublevels or caps, are called orbitals, these can be of several types
s orbytal: can hold 2 electrons
p orbytal: can hold up to 6 electrons.
d orbytal: can hold up to 10 electrons
f orbytal: can hold up to 14 electrons
g orbytal: can hold up to 18 electrons.
Depending on the row (or energy level) and the atom, we can know how many electrons can carry an element, in which period or row is, and the sub levels. For example, the Chlorine, with an atomic number of 17, can carry up to 7 electrons in it's outer level and it's on the third row (two energy levels). This can be known with it's electronic configuration:
[Cl] = 1s^2 2s^2 2p^6 3s^2 3p^5
The last energy level is 3, so it's the third period, and the electrons of those sub level are 2 and 5, 7 electrons.
Hope this can help better
If 96.0 grams of oxygen react, what mass of iron was oxidized?
A.) 32.0 g
B.) 96.0 g
C.) 167 g
D.) 223 g
Thanks!
Answer:
Explanation:
Given data:
Volume of solution = 1.5 L
Mass of solute = 61.2 g
Molar mass of solute:
= 23 + 14 + (16 × 3)
= 23 + 14 + 48
= 85 g/mol
Required:
Molarity = ?
Formula:
Solution:
First, we have to find moles of solute.
We know that,
Moles = mass / molar mass
Moles = 61.2 / 85
Moles = 0.72 moles
Now, finding molarity:
Molarity = 0.72 / 1.5
The molarity of the 1.5 L solution of sodium nitrate containing 61.2 g of NaNO3 is approximately **0.480 M**
To calculate the molarity (M) of a solution, you can use the formula:
- Volume of solution (\( V \)) = 1.5 L
- Mass of sodium nitrate = 61.2 g
- Molar mass of sodium nitrate = 85 g/mol (Na: 23 g/mol, N: 14 g/mol, O: 16 g/mol)
First, calculate the moles of sodium nitrate using its molar mass:
Now, substitute the values into the molarity formula:
So, the molarity of the 1.5 L solution of sodium nitrate containing 61.2 g of NaNO3 is approximately **0.480 M**.
To know more about molarity refer here:
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