Suppose you are going to graph the data in the table below. What data should be represented on each axis, and what would be the appropriate increments? (2 points)
Reporting periods Sales
Jan.–Mar., 2010 $100,000
Apr.–Jun., 2010 $55,000
Jul.–Sep., 2010 $45,000
Oct.–Dec., 2010 $110,000
Jan.–Mar., 2011 $330,000
Apr.–Jun., 2011 $800,000
Jul.–Sep., 2011 $242,000
Oct.–Dec., 2011 $150,000
x-axis: time period in increments of 1 month; y-axis: sales in increments of $1,000
x-axis: sales in increments of $1,000; y-axis: time period in increments of 1 month
x-axis: time period in increments of 3 months; y-axis: sales in increments of $100,000
x-axis: sales in increments of $100,000; y-axis: time period in increments of 3 months
Answer:
Yes my son they do so yeah
Step-by-step explanation:
Cuz I know
b) (-3.5, 3)
c) (-5,0)
d) (-6,-2)
The length of the diagonal cut is calculated using the Pythagorean theorem. The sides of the paper form two sides of a right-angled triangle, and by squaring and adding these lengths, then taking the square root of the result, we find that the hypotenuse, or diagonal, is 20 inches long.
In mathematics, particularly in geometry, the Pythagorean theorem is the fundamental principle used to calculate the length of the hypotenuse in a right-angled triangle. In this question, the sheet of paper can be considered a rectangle and when it is cut from one corner to the opposite corner, it forms two right-angled triangles.
The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. This can be written as: a² + b² = c²
Here, the length and width of the paper represent the two sides of the triangle, 16 inches and 12 inches respectively, and the diagonal cut (we'll call it 'd') is the hypotenuse. Thus, the equation becomes:
12² (which equals 144) + 16² (which equals 256) equals d²
Adding 144 and 256 gives 400, so d² = 400. To find 'd', we take the square root of 400, which is 20.
So, the length of the diagonal cut that Luke made is 20 inches.
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To solve for n in the equation d + 3n = 1, isolate n by subtracting d from both sides and then divide by 3.
To solve for n in the equation d + 3n = 1, we need to isolate the variable n. Start by subtracting d from both sides of the equation:
d + 3n - d = 1 - d
Simplify:
3n = 1 - d
Next, divide both sides of the equation by 3 to get the value of n:
n = (1 - d)/3
So, the solution for n is (1 - d)/3.
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