What is the value of a in the equation a=3a + 12?

Answers

Answer 1
Answer:     a = 3a + 12
- 3a  - 3a
 -2a = 12
  -2      -2
     a = -6

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The curve through the ordered pairs (0, 10), (1, 5), and (2, 2.5) can be represented by the function f(x) = 10(0.5)x. What is the multiplicative rate of change of the function?A.0.5
B.2
C.2.5
D.5

Answers

y=mx+b
trial and error tells us
f(x)=-0.25x+10 (the given equation doesn't give the correct starting value)

rate of change is -0.25

Answer:

0.5

Step-by-step explanation:

Hope this helps

Can someone please show how to solve this ln(5x-1)+ln(x-6)=ln6 ???

Answers

when you add ln, you multiply
ln((5x-1)(x-6)=ln6  do now FOIL
ln(5x^2-30x-x+6)=ln6
therefore
5x^2-31x+6=6 and 
5x^2-31x=0 furthermore 
x(5x-31)=0
one solution is 0, which we will reject
the other solution is 5x=31
x=31/5
ln(5x - 1) + ln(x - 6) = ln(6)
ln((5x - 1)(x - 6)) = ln(6)
            ln(5x(x - 6) - 1(x - 6) = ln(6)
ln(5x(x) - 5x(6) - 1(x) - 1(-6)) = ln(6)
ln(5x² - 30x - x + 6) = lm(6)
ln(5x² - 31x + 6) = ln(6)
     5x² - 31x + 6 = 6
5x² - 31x + 6 - 6 = 6 - 6
     5x² - 31x + 0 = 0
x = -(-31) +/- √((-31)² - 4(5)(0))
                       2(5)
x = 31 +/- √(961 - 0)
                 10
x = 31 +/- √(961)
              10
x = 31 +/- 31
           10
x = 31 + 31    x = 31 - 31
          10                  10
x = 62             x = 0
      10                  10
x = 6²/₅            x = 0

I have a Triangle and I need to find the side BC?

Answers

Looking at this problem in the book, I'm guessing that you've been
introduced to a little bit of trigonometry.  Or at least you've seen the
definitions of the trig functions of angles.

Do you remember the definition of either the sine or the cosine of an angle ?

In a right triangle, the sine of an acute angle is  (opposite side) / (hypotenuse),
and the cosine of an acute angle is (adjacent side) / (hypotenuse).

Maybe you could use one of these to solve this problem, but first you'd need to
make sure that this is a right triangle.

Let's see . . . all three angles in any triangle always add up to 180 degrees.
We know two of the angles in this triangle ... 39 and 51 degrees.
How many degrees are left over for the third angle ?
180 - (39 + 51) = 180 - (90) = 90 degrees for the third angle.
It's a right triangle !  yay !  We can use sine or cosine if we want to.

Let's use the 51° angle.
The cosine of any angle is (adjacent side) / (hypotenuse) .
'BC' is the side adjacent to the 51° angle in the picture,
  and the hypotenuse is 27 .

cosine(51°) = (side BC) / 27

Multiply each side of that equation by 27 :

Side-BC = (27) times cosine(51°)

Look up the cosine of 51° in a book or on your calculator.

Cosine(51°) = 0.62932 (rounded)

Side BC = (27) x (0.62932) = 16.992 (rounded)
============================================

You could just as easily have used the sine of 39° .
That would be (opposite side) / (hypotenuse) ... also (side-BC) / 27 .

Solve for f please. c=5/9 (f-32) show work thank u (:

Answers

               C = 5/9(F - 32)

Multiply each side by  9/5 :      9/5 C = F - 32

Add 32 to each side:                9/5 C + 32  =  F
c=5/9 (f-32)
c = 5/9f-160/9 /*9
9c=5f-160
5f-160=9c
5f=9c+160 /: 5
f = (9c+160)/5


A picture frame is 18 inches long and 8 inches tall. It is 2 inches wide on all 4 side. What is the area of the picture frame?

Answers

x=18-2\cdot2=18-4=14\ (in)\n\ny=8-2\cdot2=8-4=4\ (in)\n\nA=xy\to A=14\cdot4=56\ (in^2)

Answer:88

Step-by-step explanation:

The area of the whole image is 144, the area of the picture is 56. Subtracting those from each other, you get that the picture frame is 88.

H ( t) = -10 + 6 h ( ) = -44

Answers

Answer:

-44

Step-by-step explanation: