When two chairs will be removed from each table, then there would be 252 chairs left in the cafeteria.
Dividend = Divisor × Quotient + Remainder.
For given question,
total number of chairs = 294
there are 14 chairs at each table.
So, to find the number of tables in the cafeteria we need to divide total number chairs by 14.
The number of table would be,
= 294/14
= 21
This means, there are 21 tables.
If we remove two chairs from each table, then number of chairs at each table would be 14 - 2 = 12
So, the total number of chairs left in the cafeteria would be,
= 21 × 12
= 252
Hence, there will be 252 chairs left in the cafeteria.
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Answer:
252
Step-by-step explanation:
because there are 14 chairs at each table => there are: 294/14= 21 (tables)
two chairs will be removed from each table => the number of chairs removed are: 21.2 = 42 (chairs)
the chairs will be left in the cafeteria are: 294 - 42 = 252( chairs)
The probability of rolling an odd number the first time and a number greater than 4 the second time is 1/6
The sample space of a single die is
So, the total sample is 6
The odd numbers are
--- 3 odd numbers.
So, the probability of selecting an odd number is:
Simplify
The numbers greater than 4 are
--- 2 numbers greater than 4.
So, the probability of selecting a number greater than 4 is:
Simplify
The probability of rolling an odd number the first time and a number greater than 4 the second time is calculated as follows:
So, we have:
Hence, the probability is 1/6
Read more about probabilities at:
Answer: 1/6
Step-by-step explanation:
A die has 6 numbers which are 1, 2, 3, 4, 5 and 6.
Odd numbers in a die = 1, 3 and 6
Numbers greater than 4 = 5 and 6
Probability of rolling an odd number = 3/6 = 1/2
Probability of rolling a number greater than 4 = 2/6 = 1/3
We then multiply both values gotten. This will be:
= 1/2 × 1/3
= 1/6
Therefore, the probability of rolling an odd number the first time and a number greater than 4 the second time is 1/6.
Step-by-step explanation: