a school has 294 chairs.there are 14 chairs at each table. two chairs will be removed from each table.how many chairs will be left in the cafeteria?

Answers

Answer 1
Answer:

When two chairs will be removed from each table, then there would be 252 chairs left in the cafeteria.

The dividend divisor quotient remainder formula:

Dividend = Divisor × Quotient + Remainder.

For given question,

total number of chairs = 294

there are 14 chairs at each table.

So, to find the number of tables in the cafeteria we need to divide total number chairs by 14.

The number of table would be,

= 294/14

= 21

This means, there are 21 tables.

If we remove two chairs from each table, then number of chairs at each table would be 14 - 2 = 12

So, the total number of chairs left in the cafeteria would be,

= 21 × 12

= 252

Hence, there will be 252 chairs left in the cafeteria.

Learn more about division here:

brainly.com/question/2272590

#SPJ2

Answer 2
Answer:

Answer:

252

Step-by-step explanation:

because there are 14 chairs at each table => there are: 294/14= 21 (tables)

two chairs will be removed from each table => the number of chairs removed are: 21.2 = 42 (chairs)

the chairs  will be left in the cafeteria are: 294 - 42 = 252( chairs)


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How much sales tax will Nicole pay on a $36 shirt if the tax rate is 7%?

Answers

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(7/100) * 36

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a school has a policy that 2 adults must accompany every group of 15 students on school trips. how many adults are needed to take 180 students on a trip?

Answers

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A single die is rolled twice. Find the probability of rolling an Odd number the first time and a number greater than 4 the second time.

Answers

The probability of rolling an  odd number the first time and a number greater than 4 the second time is 1/6

The sample space of a single die is

\mathbf{S = \{1,2,3,4,5,6\}}

So, the total sample is 6

The odd numbers are

\mathbf{Odd = \{1,3,5\}} --- 3 odd numbers.

So, the probability of selecting an odd number is:

\mathbf{P(Odd) = \frac 36}

Simplify

\mathbf{P(Odd) = \frac 12}

The numbers greater than 4 are

\mathbf{Greater = \{5,6\}} --- 2 numbers greater than 4.

So, the probability of selecting a number greater than 4 is:

\mathbf{P(Greater) = \frac 26}

Simplify

\mathbf{P(Greater) = \frac 13}

The probability of rolling an  odd number the first time and a number greater than 4 the second time is calculated as follows:

\mathbf{P = P(Odd) * P(Greater)}

So, we have:

\mathbf{P = \frac 12 * \frac 13}

\mathbf{P = \frac 16}

Hence, the probability is 1/6

Read more about probabilities at:

brainly.com/question/11234923

Answer: 1/6

Step-by-step explanation:

A die has 6 numbers which are 1, 2, 3, 4, 5 and 6.

Odd numbers in a die = 1, 3 and 6

Numbers greater than 4 = 5 and 6

Probability of rolling an odd number = 3/6 = 1/2

Probability of rolling a number greater than 4 = 2/6 = 1/3

We then multiply both values gotten. This will be:

= 1/2 × 1/3

= 1/6

Therefore, the probability of rolling an odd number the first time and a number greater than 4 the second time is 1/6.

What is the solution to the system of equations

Answers

Step-by-step explanation:

5x + 3y = 13 \n 7x + 8y =  - 16 \n 5x = 13 - 3y \n x =  (13 - 3y)/(5)  \n 7( (13 - 3y)/(5) ) + 8y =  - 16 \n 18.2 - 4.2y + 8y =  - 16 \n 3.8y =  - 34.2 \n y =  - 9 \n

x =  (13 - 3( - 9))/(5)  =  (13 + 27)/(5)  =  (40)/(5)  = 8 \n x = 8 \n y =  - 9

A population of rabbits has a mean life span of 10 years with a standard deviation of 2.6 days. If a sample of 30 rabbits is taken from this population, what is the probability the sample will have a sample mean life span of less than 9 years rounded to the nearest tenth of a percent? (Do not type in the percent symbol)

Answers

Rabbits was a good night to see how you are your dad is going to be happy

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Answers

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y - sons age
now : x=2y
in six years: x+6=3(y-6)
we subsitude to second equation x=2y
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-y=-24 /:(-1)
y=24
x=2*24=48
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