CHEMISTRY COLLEGE

How many chlorine atoms are there in 2 molecules of ICl?

Answers

Answer 1
Answer:

Answer: 38 chlorine atoms are in 3 molecules of HCI

Explanation:
Answer 2
Answer:

Final answer:

In 2 molecules of ICl, there would be 2 atoms of Chlorine, as the subscript of Chlorine in the compound ICl is 1.

Explanation:

In a compound, the subscript of an element indicates the number of atoms of that element present per molecule of the compound. For the ICl compound, there is one atom of Chlorine in one molecule. Therefore, in 2 molecules of ICl, there would be 2*1 = 2 atoms of Chlorine.

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An imaginary line dividing the earth's surface into two hemisphere the northern and southern hemisphere, it is locatedat 0⁰, which of the following imaginary lines is being described? a.equator b.latitude c.longitude d.prime meridian​
Draw the Lewis structure for the polyatomic hydronium H3O cation. Be sure to include all resonance structures that
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A 99.8 mL sample of a solution that is 12.0% KI by mass (d: 1.093 g/mL) is added to 96.7 mL of another solution that is 14.0% Pb(NO3)2 by mass (d: 1.134 g/mL). How many grams of PbI2 should form?Pb(NO3)2(aq) + 2 KI(aq) PbI2(s) + 2 KNO3(aq)

Weathering and erosion can turn metamorphic rock into sediment. Which of the following processes would turn that sediment into sedimentary rock? * 10 points weathering and erosion compaction and cementation heat and pressure melting

Answers

Answer:

compaction and cementation

Explanation:

sedimentary rock is layered rock, in order to become sedimentary it most be compacted to form layers and cemented to become hard. This is what i think. Hope i can help :)

A chemical equation is balanced when thesubscripts of the reactants equal the subscripts of the products,
coefficients of the reactants equal the coefficients of the products,
products and reactants are the same chemicals,
same number of each kind of atom appears in the reactants and in the products,

Answers

same number of each kind of atom appears in the reactants and in the products

A natural atom possesses the atomic number of 13 and a atomic mass of 27. Three electrons are lost. From what region of the atom are they lost?

Answers

Answer:

The electrons are lost from the valence shell (outermost electron shell) of the atom.

Explanation:

This is able to be inferred not only because valence electrons being lost first is a trend but also because the atom in question has actually 3 valence electrons (13-2-8 = 3).

How much work is done in lifting a 2kg objext to a height of 1m​

Answers

Answer:

19.6 J

Explanation:

The following data were obtained from the question:

Mass (m) of object = 2 Kg

Height (h) = 1 m

Workdone =?

NOTE: Acceleration due to gravity (g) = 9.8 m/s²

Thus, we can obtain the workdone in lifting the object by using the following formula:

Workdone = mgh

Workdone = 2 × 9.8 × 1

Workdone = 19.6 J

Therefore, the workdone in lifting the object to height of 1 m is 19.6 J

A solution in which the pH is 1.6 would be described asa.
very acidic
b.
slightly acidic
c.
very basic
d.
slightly basic
e.
neutral

Answers

Answer:

a.  very acidic

Explanation:

A solution with a pH of 1.6 would be described as a very acidic solution.

The pH scale is a convenient scale for expressing the level of acidity or alkalinity of aqueous solutions.

The scale ranges from 1 to 14 in which case 1 is the lower limit and 14 the upper limit.  

  • An acidic solution has a pH value less than 7. As pH decreases, the acidity of the solution increases.
  • Neutral solutions have a pH of 7
  • An alkaline solution has a pH greater than 7 and the level of alkalinity increases as pH increases.

If the mass percentage composition of a compound is 72.1% Mn and 27.9% O, its empirical formula is

Answers

Answer:

MnO- Manganese Oxide

Explanation:

Empirical formula: This is the formula that shows the ratio of elements

present in a  

compound.

   

How to determine Empirical formula

1. First arrange the symbols of the elements present in the compound

alphabetically to  determine the real empirical formula. Although, there

are exceptions to this rule, E.g H2So4

2. Divide the percentage composition by the mass number.

3. Then divide through by the smallest number.

4. The resulting answer is the ratio attached to the elements present in

a compound.

           

                                                                              Mn                         O    

                         

% composition                                                      72.1                      27.9    

                       

Divide by mass number                                       54.94                     16  

                                 

                                                                               1.31                      1.74    

                       

Divide by the smallest number                         1.31                      1.31                          

                                                                               1                    1.3

                                                 

The resulting ratio is 1:1

 

Hence the Empirical formula is MnO, Manganese oxide
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